Morphocompletion for #3741 ⟨a, b | abaabbaaab=a

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaaab ⇒ abaaaaa
2. aaaaaaab ⇒ aabaaaaa
3. aabaaaaab ⇒ abaaaaaba
4. aaabbaaa ⇒ abaaaaab
5. aaabbaaaa ⇒ aabaaaaab
6. aaaabb ⇒ aaabba
7. aaabbaaab ⇒ abaabbaaa
8. aaaababb ⇒ aaabbaba
9. aaaabaabb ⇒ aaabbabaa
10. abaabbaaab ⇒ a
11. aaabbabaabbaaa ⇒ aaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] bb, [2/3] ba
Length 3:[3/0] aaa, [3/1] aab, [3/2] abb, [3/3] baa, [3/4] bba, [3/5] aba, [3/6] bab
Length 4:[4/0] aaab, [4/1] aaaa, [4/2] aabb, [4/3] baaa, [4/4] abba, [4/5] bbaa, [4/6] abaa
Length 5:[5/0] aaaab, [5/1] aaabb, [5/2] aaaaa, [5/3] bbaaa, [5/4] aabba, [5/5] abbaa, [5/6] baabb
Length 6:[6/0] aaabba, [6/1] abbaaa, [6/2] aaaaab, [6/3] abaabb, [6/4] aabbaa, [6/5] aaaaaa, [6/6] bbaaab
Length 7:[7/0] aabbaaa, [7/1] aaabbaa, [7/2] abbaaab, [7/3] abaabba, [7/4] aaababb, [7/5] aaabbab, [7/6] aabaabb

Considering [length 3 / frequency 2] abb=c.

Step 2

Rewriting system is complete. See a, b | abaabbaaab=a.