Morphocompletion for #3741 ⟨a, b | abaabbaaab=a⟩

Solved by morph:3/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaaab ⇒ abaaaaa
2. aaaaaaab ⇒ aabaaaaa
3. aabaaaaab ⇒ abaaaaaba
4. aaabbaaa ⇒ abaaaaab
5. aaabbaaaa ⇒ aabaaaaab
6. aaaabb ⇒ aaabba
7. aaabbaaab ⇒ abaabbaaa
8. aaaababb ⇒ aaabbaba
9. aaaabaabb ⇒ aaabbabaa
10. abaabbaaab ⇒ a
11. aaabbabaabbaaa ⇒ aaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa60lf:47,lp:10,ls:3,rf:35,rp:6,rs:4,lprp:6,lsrp:2,lprs:4
[2/1]ab25lf:19,lp:1,ls:5,rf:16,rp:4,rs:3,lsrp:3
[2/2]bb12lf:9,ls:3,rf:4
[2/3]ba11lf:11,rf:13,rs:3
[3/0]aaa40lf:28,lp:9,ls:3,rf:21,rp:4,rs:3,lprp:4,lsrp:1,lprs:3
[3/1]aab22lf:16,lp:1,ls:5,rf:10,rp:2,rs:3,lsrp:1
[3/2]abb12lf:9,ls:3,rf:4
[3/3]baa9lf:9,rf:8,rs:1
[3/4]bba6lf:6,rf:4,rs:1
[3/5]aba6lf:5,lp:1,rf:9,rp:4,rs:2
[3/6]bab2lf:2,rf:2,a:3
[4/0]aaab21lf:12,lp:4,ls:5,rf:7,rp:3,rs:3,lprs:3
[4/1]aaaa19lf:13,lp:5,ls:1,rf:11,rp:1,rs:2,lprs:2,a:3
[4/2]aabb10lf:8,ls:2,rf:4
[4/3]baaa8lf:6,ls:2,rf:6,rs:1
[4/4]abba6lf:6,rf:4,rs:1
[4/5]bbaa5lf:5,rf:1
[4/6]abaa5lf:4,lp:1,rf:7,rp:4,rs:1
[5/0]aaaab12lf:6,lp:3,ls:3,rf:4,rp:1,rs:3,re:1,a:3
[5/1]aaabb10lf:5,lp:4,ls:1,rf:3,rp:3,lsrp:10,a:1
[5/2]aaaaa8lf:6,lp:2,rf:5,rs:2,lprs:2,a:21
[5/3]bbaaa7lf:5,ls:2,rf:1,rs:1
[5/4]aabba6lf:6,rf:4,rs:1
[5/5]abbaa5lf:5,rf:1
[5/6]baabb4lf:3,ls:1,rf:1
[6/0]aaabba8lf:4,lp:4,rf:3,rp:3,rs:1,re:1,a:1
[6/1]abbaaa7lf:5,ls:2,rf:1,rs:1
[6/2]aaaaab6lf:3,ls:3,rf:3,rs:2,a:21
[6/3]abaabb5lf:3,lp:1,ls:1,rf:1,rp:1
[6/4]aabbaa5lf:5,rf:1
[6/5]aaaaaa5lf:3,lp:2,a:34
[6/6]bbaaab4lf:2,ls:2
[7/0]aabbaaa7lf:5,ls:2,rf:1,rs:1
[7/1]aaabbaa6lf:3,lp:3,a:1
[7/2]abbaaab4lf:2,ls:2
[7/3]abaabba3lf:2,lp:1,rf:1,rp:1
[7/4]aaababb2lf:1,ls:1,a:9
[7/5]aaabbab2lf:1,lp:1,rf:2,rp:2,a:3
[7/6]aabaabb2lf:1,ls:1,a:10

Considering [length 3 / frequency 2] abb=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaabbaaab=a⟩.