Morphocompletion for #3728 ⟨a, b | abaabaaaab=a⟩

Solved by morph:3/1,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaabb ⇒ abaabaa
2. aaabaaaab ⇒ abaabaaaa
3. abaabaaaab ⇒ a
4. aaaaababbaab ⇒ abaabaabaaba
5. aaaaababaaaab ⇒ aaaaabaaabbaa
6. abaabaabaabaaaa ⇒ aaaaab
7. aaaaababbbaabaaaa ⇒ aaaaabab
8. abaabaabaababaabaa ⇒ aaaaababb
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa52lf:44,lp:5,ls:3,rf:28,rp:4,rs:3,lprp:2,lsrp:3,lprs:3
[2/1]ab32lf:25,lp:3,ls:4,rf:15,rp:3,rs:2,lsrp:2,lprs:1
[2/2]ba20lf:20,rf:12,rs:1
[2/3]bb5lf:4,ls:1,rf:2,rs:1,a:5
[3/0]aaa30lf:23,lp:5,ls:2,rf:15,rp:4,rs:1,lprp:2,lsrp:2,lprs:1
[3/1]aab22lf:18,ls:4,rf:10,rs:1
[3/2]aba21lf:18,lp:3,rf:11,rp:3,rs:1
[3/3]baa17lf:16,ls:1,rf:9,rs:2
[4/0]aaaa19lf:13,lp:4,ls:2,rf:9,rp:4,rs:1,lprp:2,lsrp:2
[4/1]abaa18lf:14,lp:3,ls:1,rf:8,rp:3,rs:1
[4/2]aaba13lf:13,rf:8,rs:1
[4/3]aaab12lf:8,lp:1,ls:3,rf:5,rs:1
[5/0]abaab11lf:8,lp:3,rf:5,rp:3
[5/1]aaaab10lf:7,ls:3,rf:4,rs:1
[5/2]aabaa10lf:9,ls:1,rf:5,rs:1
[5/3]baaba9lf:9,rf:5,rs:1
[6/0]abaaba11lf:8,lp:3,rf:5,rp:3,rs:1
[6/1]baabaa9lf:8,ls:1,rf:4,rs:1
[6/2]aaaaab8lf:4,lp:4,rf:4,rp:4,rs:1,re:1,lprp:2,a:2
[6/3]abaaaa7lf:5,ls:2,rf:1,rs:1

Considering [length 3 / frequency 1] aab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccaac ⇒ aa
2. aab ⇒ c
3. aaaac ⇒ ccccaaaa
4. aacaac ⇒ ccaaaa
5. abcaac ⇒ a
6. aaacb ⇒ abcaa
7. acaacb ⇒ a
8. aaaccb ⇒ abcccccaa
9. acaaccb ⇒ abcccaa
10. aaacab ⇒ abcccaaac
11. acaacab ⇒ abcaaac
12. aaaccab ⇒ abcccccccaaac
13. acaaccab ⇒ abcccccaaac
14. acaacacb ⇒ abcaccaa
15. abcaaaa ⇒ acaac
16. abcccaaaa ⇒ aaac
17. abcccccaaaa ⇒ acaacc
18. abcccccccaaaa ⇒ aaacc
19. abcaccccaaaa ⇒ acaacac
20. abcccaccccaaaa ⇒ aaacac
...

Collecting factors up to length 6 / frequency 7:

[2/0]aa52lf:39,lp:7,ls:6,rf:28,rp:4,rs:7,re:1,lsrp:3,lprs:4,a:1
[2/1]ac31lf:22,lp:5,ls:4,rf:16,rp:3,rs:8,lprs:2,a:2
[2/2]cc26lf:25,lp:1,rf:25,rp:2,rs:2,a:3
[2/3]ab24lf:12,lp:7,ls:5,rf:8,rp:8,lsrp:4,a:1
[2/4]ca21lf:21,rf:16,a:2
[2/5]cb10lf:5,ls:5,a:8
[2/6]bc7lf:7,rf:8,a:2
[3/0]aaa29lf:18,lp:5,ls:6,rf:11,rp:3,rs:2,lsrp:3,lprs:1,a:4
[3/1]aac19lf:14,lp:1,ls:4,rf:10,rs:6,a:2
[3/2]abc14lf:7,lp:7,rf:8,rp:8,a:2
[3/3]aca14lf:9,lp:5,rf:5,rp:3,a:4
[3/4]caa14lf:14,rf:13,rs:4,a:2
[3/5]ccc14lf:14,rf:15,rp:1,a:6
[3/6]cca10lf:9,lp:1,rf:8,rp:1,a:3
[4/0]aaaa14lf:7,lp:1,ls:6,rf:2,rs:2,lprs:1,a:4
[4/1]acaa11lf:6,lp:5,rf:3,rp:3,a:4
[4/2]caac11lf:8,ls:3,rf:3,rs:1,a:2
[4/3]aaac10lf:5,lp:4,ls:1,rf:7,rp:3,rs:5,re:1,lprs:2,a:6
[4/4]abcc8lf:4,lp:4,rf:5,rp:5,a:6
[4/5]cccc8lf:8,rf:9,rp:1,a:7
[4/6]ccaa7lf:6,lp:1,rf:8,rp:1,rs:3,a:3
[5/0]caaaa12lf:6,ls:6,rf:2,rs:2,a:4
[5/1]acaac12lf:6,lp:5,ls:1,rf:3,rp:3,rs:1,re:1,a:4
[5/2]abccc8lf:4,lp:4,rf:5,rp:5,a:6
[5/3]ccaaa5lf:5,rf:5,rp:1,a:5
[5/4]cccaa5lf:5,rf:6,rs:2,a:6
[5/5]aacab4lf:2,ls:2,a:9
[5/6]abcaa4lf:2,lp:2,rf:2,rp:2,rs:1,re:1,a:2

Considering [length 4 / frequency 0] aaaa=d.

Step 3

Rewriting system is complete. See ⟨a, b | abaabaaaab=a⟩.