| Back: | ⟨a, b | abaaaaaaab=b⟩ |
|---|
Completion settings:
Axiom: abaaaaaaab=b.
Referenced by [2], [3], [4], [5], [6], [7], [8], [9].
Overlap of [1] abaaaaaaab=b with [1] abaaaaaaab=b:
Critical pair: abaaaaaab=baaaaaaab.
Flip LHS and RHS.
Overlap of [2] baaaaaaab=abaaaaaab with [1] abaaaaaaab=b:
Critical pair: baaaaaab=abaaaaaabaaaaaaab.
Reduce RHS:
| [1] | abaaaaa(abaaaaaaab) |
| ⇒ abaaaaab |
Referenced by [4], [9], [10], [11].
Overlap of [3] baaaaaab=abaaaaab with [1] abaaaaaaab=b:
Critical pair: baaaaab=abaaaaabaaaaaaab.
Reduce RHS:
| [1] | abaaaa(abaaaaaaab) |
| ⇒ abaaaab |
Referenced by [5], [9], [10], [11], [12].
Overlap of [4] baaaaab=abaaaab with [1] abaaaaaaab=b:
Critical pair: baaaab=abaaaabaaaaaaab.
Reduce RHS:
| [1] | abaaa(abaaaaaaab) |
| ⇒ abaaab |
Referenced by [6], [9], [10], [11], [12], [13].
Overlap of [5] baaaab=abaaab with [1] abaaaaaaab=b:
Critical pair: baaab=abaaabaaaaaaab.
Reduce RHS:
| [1] | abaa(abaaaaaaab) |
| ⇒ abaab |
Referenced by [7], [9], [10], [11], [12], [13], [14].
Overlap of [6] baaab=abaab with [1] abaaaaaaab=b:
Critical pair: baab=abaabaaaaaaab.
Reduce RHS:
| [1] | aba(abaaaaaaab) |
| ⇒ abab |
Referenced by [8], [9], [10], [11], [12], [13], [14], [15].
Overlap of [7] baab=abab with [1] abaaaaaaab=b:
Critical pair: bab=ababaaaaaaab.
Reduce RHS:
| [1] | ab(abaaaaaaab) |
| ⇒ abb |
Defines rule #1.
Referenced by [9], [10], [11], [12], [13], [14], [15].
Overlap of [1] abaaaaaaab=b with [2] baaaaaaab=abaaaaaab:
Critical pair: aabaaaaaab=b.
Reduce LHS:
| [3] | aa(baaaaaab) |
| [4] | ⇒ aaa(baaaaab) |
| [5] | ⇒ aaaa(baaaab) |
| [6] | ⇒ aaaaa(baaab) |
| [7] | ⇒ aaaaaa(baab) |
| [8] | ⇒ aaaaaaa(bab) |
| ⇒ aaaaaaaabb |
Defines rule #8.
Simplify [2] baaaaaaab=abaaaaaab.
Reduce RHS:
| [3] | a(baaaaaab) |
| [4] | ⇒ aa(baaaaab) |
| [5] | ⇒ aaa(baaaab) |
| [6] | ⇒ aaaa(baaab) |
| [7] | ⇒ aaaaa(baab) |
| [8] | ⇒ aaaaaa(bab) |
| ⇒ aaaaaaabb |
Defines rule #7.
Simplify [3] baaaaaab=abaaaaab.
Reduce RHS:
| [4] | a(baaaaab) |
| [5] | ⇒ aa(baaaab) |
| [6] | ⇒ aaa(baaab) |
| [7] | ⇒ aaaa(baab) |
| [8] | ⇒ aaaaa(bab) |
| ⇒ aaaaaabb |
Defines rule #6.
Simplify [4] baaaaab=abaaaab.
Reduce RHS:
| [5] | a(baaaab) |
| [6] | ⇒ aa(baaab) |
| [7] | ⇒ aaa(baab) |
| [8] | ⇒ aaaa(bab) |
| ⇒ aaaaabb |
Defines rule #5.
Simplify [5] baaaab=abaaab.
Reduce RHS:
| [6] | a(baaab) |
| [7] | ⇒ aa(baab) |
| [8] | ⇒ aaa(bab) |
| ⇒ aaaabb |
Defines rule #4.
Simplify [6] baaab=abaab.
Reduce RHS:
| [7] | a(baab) |
| [8] | ⇒ aa(bab) |
| ⇒ aaabb |
Defines rule #3.
Simplify [7] baab=abab.
Reduce RHS:
| [8] | a(bab) |
| ⇒ aabb |
Defines rule #2.