Morphocompletion for #3679 ⟨a, b | aabbbbaaab=a⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaaab ⇒ aabbbbaa
2. aaaababbbb ⇒ a
3. aabbbbaaa ⇒ aaaababbb
4. abaaaba ⇒ aaaabab
5. abbaaaba ⇒ aaaababb
6. aaaababaababbb ⇒ abaaa
7. aaaababbabbbbaa ⇒ abaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa26lf:20,lp:4,ls:2,rf:15,rp:4,rs:2,lprp:1,lsrp:1,lprs:1,a:1
[2/1]ab20lf:16,lp:3,ls:1,rf:10,rp:2,rs:2,lprs:1,a:1
[2/2]bb17lf:15,ls:2,rf:6,rs:2,a:1
[2/3]ba15lf:13,ls:2,rf:6,a:1
[3/0]aaa14lf:10,lp:3,ls:1,rf:8,rp:3,rs:1,lsrp:1,lprs:1,a:1
[3/1]aba11lf:8,lp:1,ls:2,rf:5,rp:2,a:8
[3/2]aab10lf:8,lp:1,ls:1,rf:5,rp:1,rs:1,lsrp:1,a:1
[3/3]bbb10lf:8,ls:2,rf:3,rs:1,a:1
[3/4]abb9lf:7,lp:2,rf:3,rs:1,lprs:1,a:1
[3/5]baa7lf:6,ls:1,rf:3,rs:1,a:1
[3/6]bba5lf:5,rf:1,a:1
[4/0]aaba8lf:6,ls:2,rf:3,a:8
[4/1]aaab7lf:6,ls:1,rf:4,rs:1,a:1
[4/2]abbb7lf:5,lp:1,ls:1,rf:2,rs:1,a:1
[4/3]aaaa6lf:3,lp:3,rf:3,rp:3,a:8
[4/4]baaa5lf:4,ls:1,rf:2,rs:1,a:1
[4/5]bbaa5lf:4,ls:1,rf:1,rs:1,a:1
[4/6]abab4lf:4,rf:3,rs:1,a:8
[5/0]aaaba7lf:5,ls:2,rf:3,a:8
[5/1]aaaab6lf:3,lp:3,rf:3,rp:3,a:8
[5/2]bbaaa4lf:3,ls:1,a:1
[5/3]baaab4lf:3,ls:1,rf:1,rs:1,a:1
[5/4]aabab4lf:4,rf:3,rs:1,a:8
[5/5]bbbaa4lf:3,ls:1,rf:1,rs:1,a:1
[5/6]babbb4lf:3,ls:1,rf:1,rs:1,a:10
[6/0]aaaaba6lf:3,lp:3,rf:3,rp:3,a:8
[6/1]baaaba4lf:2,ls:2,a:8
[6/2]aaabab3lf:3,rf:3,rs:1,a:8
[6/3]bbbaaa3lf:2,ls:1,a:1
[6/4]bbaaab3lf:2,ls:1,a:1
[6/5]aababb3lf:3,rf:2,rs:1,a:8
[6/6]bbbbaa3lf:2,ls:1,rf:1,rs:1,a:1
[7/0]aaaabab6lf:3,lp:3,rf:3,rp:3,rs:1,re:1,a:8
[7/1]abbbbaa3lf:2,ls:1,rf:1,rs:1,a:1
[7/2]aababbb3lf:2,ls:1,rf:1,rs:1,a:22
[7/3]bbaaaba2lf:1,ls:1,a:8
[7/4]abbbaaa2lf:1,lp:1,a:1
[7/5]abbaaab2lf:1,lp:1,a:8
[7/6]aaababb2lf:2,rf:2,rs:1,a:8

Considering [length 3 / frequency 0] aaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbbaaab=a⟩.