Morphocompletion for #3679 ⟨a, b | aabbbbaaab=a⟩

Back:⟨a, b | aabbbbaaab=a⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaaab ⇒ aabbbbaa
2. aaaababbbb ⇒ a
3. aabbbbaaa ⇒ aaaababbb
4. abaaaba ⇒ aaaabab
5. abbaaaba ⇒ aaaababb
6. aaaababaababbb ⇒ abaaa
7. aaaababbabbbbaa ⇒ abaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] bb, [2/3] ba
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] bbb, [3/4] abb, [3/5] baa, [3/6] bba
Length 4:[4/0] aaba, [4/1] aaab, [4/2] abbb, [4/3] aaaa, [4/4] baaa, [4/5] bbaa, [4/6] abab
Length 5:[5/0] aaaba, [5/1] aaaab, [5/2] bbaaa, [5/3] baaab, [5/4] aabab, [5/5] bbbaa, [5/6] babbb
Length 6:[6/0] aaaaba, [6/1] baaaba, [6/2] aaabab, [6/3] bbbaaa, [6/4] bbaaab, [6/5] aababb, [6/6] bbbbaa
Length 7:[7/0] aaaabab, [7/1] abbbbaa, [7/2] aababbb, [7/3] bbaaaba, [7/4] abbbaaa, [7/5] abbaaab, [7/6] aaababb

Considering [length 3 / frequency 0] aaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbbaaab=a⟩.