Morphocompletion for #3671 ⟨a, b | aabbbabaab=a

Solved by morph:2/0,2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbbaba ⇒ aaababbb
2. abbabaa ⇒ aaababb
3. aaababbbab ⇒ a
4. aabaababb ⇒ aaababbba
5. ababaaba ⇒ aabaabab
6. aaababbababbbab ⇒ abbaba
7. aabaababababbb ⇒ ababa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] abb
Length 4:[4/0] aaba, [4/1] abab, [4/2] baba, [4/3] bbab
Length 5:[5/0] ababb, [5/1] bbbab, [5/2] aabaa, [5/3] aaaba
Length 6:[6/0] abbbab, [6/1] abaaba, [6/2] aabaab, [6/3] aaabab

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ab ⇒ c
2. ccaccb ⇒ a
3. ccaccccbbb ⇒ cbcc
4. ccacccbbcc ⇒ ccacb
5. ccaccccbbcc ⇒ a
6. cbca ⇒ ccaccccbb
7. aaccbb ⇒ ccaccccbbc
8. aacccbbcc ⇒ aacb
9. aaccccbbcc ⇒ aaccb
10. acaccb ⇒ ccacc
11. acbbca ⇒ ccaccccbbc
12. ccaca ⇒ acacc
13. ccacccbbca ⇒ ccac
14. aacccbbca ⇒ aac
15. acaca ⇒ ccacccacc
16. acacccbbca ⇒ acac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] ca, [2/2] ac, [2/3] cb, [2/4] bb, [2/5] bc, [2/6] aa
Length 3:[3/0] ccb, [3/1] cca, [3/2] acc, [3/3] cbb, [3/4] ccc, [3/5] aca, [3/6] bca
Length 4:[4/0] ccac, [4/1] ccbb, [4/2] aacc, [4/3] bbca, [4/4] accc, [4/5] bbcc, [4/6] cbbc
Length 5:[5/0] ccacc, [5/1] cbbca, [5/2] cbbcc, [5/3] cccbb, [5/4] ccbbc, [5/5] aaccc, [5/6] caccc

Considering [length 2 / frequency 1] ca=d.

Step 3

Rewriting system is complete. See a, b | aabbbabaab=a.