Morphocompletion for #3665 ⟨a, b | aabbbaaaba=b

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. babbbaaaba ⇒ aabbbaaabb
2. aabbbaaaba ⇒ b
3. bbbbaaababaaaba ⇒ aabbbaaaaabbbab
4. babbbaaaaabbbaaabb ⇒ aabbbaaabbbbbaaaba
5. aabbbaaaaabbbaaabb ⇒ bbbbaaaba
6. bbbbaaababaaaaabbbaaabb ⇒ aabbbaaaaabbbabbbbaaaba
7. babbbaaaaabbbaaaaabbbaaaaabbbab ⇒ aabbbaaabbbbbaaababbaaababaaaba
8. aabbbaaaaabbbaaaaabbbaaaaabbbab ⇒ bbbbaaababbaaababaaaba
9. bbbbaaababaaaaabbbaaaaabbbaaaaabbbab ⇒ aabbbaaaaabbbabbbbaaababbaaababaaaba
10. bbbbaaababbaaababaaababbaaababaaaba ⇒ aabbbaaaaabbbaaaaabbbaaaaabbaabbbab
11. babbbaaaaabbbaaaaabbbaaaaabbaabbbaaabb ⇒ aabbbaaabbbbbaaababbaaababaaababbaaaba
12. aabbbaaaaabbbaaaaabbbaaaaabbaabbbaaabb ⇒ bbbbaaababbaaababaaababbaaaba
13. bbbbaaababaaaaabbbaaaaabbbaaaaabbaabbbaaabb ⇒ aabbbaaaaabbbabbbbaaababbaaababaaababbaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] bb, [2/2] ba, [2/3] ab
Length 3:[3/0] aaa, [3/1] aab, [3/2] abb, [3/3] bbb, [3/4] baa, [3/5] bba, [3/6] aba
Length 4:[4/0] aabb, [4/1] aaaa, [4/2] baaa, [4/3] aaab, [4/4] bbaa, [4/5] bbba, [4/6] abbb
Length 5:[5/0] bbaaa, [5/1] aaabb, [5/2] bbbaa, [5/3] abbba, [5/4] aabbb, [5/5] aaaaa, [5/6] baaaa
Length 6:[6/0] bbbaaa, [6/1] aabbba, [6/2] abbbaa, [6/3] baaaaa, [6/4] aaaaab, [6/5] aaaabb, [6/6] bbaaaa
Length 7:[7/0] abbbaaa, [7/1] aabbbaa, [7/2] baaaaab, [7/3] aaaaabb, [7/4] bbaaaaa, [7/5] bbbaaaa, [7/6] aaabbba

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See a, b | aabbbaaaba=b.