Morphocompletion for #3662 ⟨a, b | aabbbaaaab=a⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaaab ⇒ aabbbaaa
2. aaaaababbb ⇒ a
3. aabbbaaaa ⇒ aaaaababb
4. abaaaaba ⇒ aaaaabab
5. aaaaababbababbb ⇒ aabbba
6. aaaaababbaababbb ⇒ aabbbaa
7. aaaaabaaababbba ⇒ aaaaab
8. aaaaababaababbba ⇒ abaaaab
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa41lf:34,lp:6,ls:1,rf:21,rp:6,rs:2,lprp:4,lsrp:1,lprs:1,a:1
[2/1]ab25lf:22,lp:2,ls:1,rf:10,rp:1,rs:3,lprs:1,a:1
[2/2]ba21lf:18,ls:3,rf:6,rs:1,a:1
[2/3]bb18lf:15,ls:3,rf:7,rs:1,a:1
[3/0]aaa28lf:22,lp:5,ls:1,rf:12,rp:3,rs:1,lprp:1,lsrp:1,a:1
[3/1]aba14lf:12,lp:1,ls:1,rf:3,rp:1,a:8
[3/2]aab13lf:11,lp:1,ls:1,rf:7,rp:3,rs:2,lsrp:1,a:1
[3/3]abb10lf:9,lp:1,rf:4,rs:1,a:1
[3/4]bab9lf:9,rf:2,rs:1,a:8
[3/5]bbb9lf:6,ls:3,rf:3,a:1
[3/6]bba8lf:6,ls:2,rf:3,rs:1,a:1
[4/0]aaaa19lf:13,lp:5,ls:1,rf:7,rp:3,lprp:1,lsrp:1,a:1
[4/1]aaba10lf:9,ls:1,rf:2,a:8
[4/2]aaab9lf:8,ls:1,rf:4,rs:2,a:1
[4/3]abbb9lf:6,ls:3,rf:3,a:1
[4/4]abab8lf:8,rf:2,rs:1,a:8
[4/5]babb7lf:7,rf:1,rs:1,a:14
[4/6]bbba5lf:3,ls:2,rf:3,rs:1,a:1
[5/0]aaaaa10lf:5,lp:5,rf:3,rp:3,lprp:1,a:8
[5/1]aaaba8lf:7,ls:1,rf:2,a:8
[5/2]aaaab8lf:7,ls:1,rf:4,rs:2,a:1
[5/3]babbb8lf:5,ls:3,a:17
[5/4]aabab7lf:7,rf:2,rs:1,a:8
[5/5]ababb7lf:7,rf:1,rs:1,a:14
[5/6]abbba5lf:3,ls:2,rf:3,rs:1,a:1
[6/0]aaaaab10lf:5,lp:5,rf:3,rp:3,rs:1,re:1,lprp:1,lprs:1,a:8
[6/1]ababbb8lf:5,ls:3,a:17
[6/2]aaaaba7lf:6,ls:1,rf:2,a:8
[6/3]aababb6lf:6,rf:1,rs:1,a:14
[6/4]aaabab5lf:5,rf:2,rs:1,a:8
[6/5]babbba4lf:2,ls:2,a:33
[6/6]bbaaaa3lf:2,ls:1,a:1
[7/0]aaaaaba10lf:5,lp:5,rf:2,rp:2,a:8
[7/1]aababbb6lf:4,ls:2,a:17
[7/2]aaaabab4lf:4,rf:2,rs:1,a:8
[7/3]aaababb4lf:4,rf:1,rs:1,a:14
[7/4]ababbba4lf:2,ls:2,a:33
[7/5]baaaaba2lf:1,ls:1,a:8
[7/6]abbaaaa2lf:1,lp:1,a:1

Considering [length 4 / frequency 0] aaaa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbbaaaab=a⟩.