Morphocompletion for #3662 ⟨a, b | aabbbaaaab=a

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaaab ⇒ aabbbaaa
2. aaaaababbb ⇒ a
3. aabbbaaaa ⇒ aaaaababb
4. abaaaaba ⇒ aaaaabab
5. aaaaababbababbb ⇒ aabbba
6. aaaaababbaababbb ⇒ aabbbaa
7. aaaaabaaababbba ⇒ aaaaab
8. aaaaababaababbba ⇒ abaaaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aba, [3/2] aab, [3/3] abb, [3/4] bab, [3/5] bbb, [3/6] bba
Length 4:[4/0] aaaa, [4/1] aaba, [4/2] aaab, [4/3] abbb, [4/4] abab, [4/5] babb, [4/6] bbba
Length 5:[5/0] aaaaa, [5/1] aaaba, [5/2] aaaab, [5/3] babbb, [5/4] aabab, [5/5] ababb, [5/6] abbba
Length 6:[6/0] aaaaab, [6/1] ababbb, [6/2] aaaaba, [6/3] aababb, [6/4] aaabab, [6/5] babbba, [6/6] bbaaaa
Length 7:[7/0] aaaaaba, [7/1] aababbb, [7/2] aaaabab, [7/3] aaababb, [7/4] ababbba, [7/5] baaaaba, [7/6] abbaaaa

Considering [length 4 / frequency 0] aaaa=c.

Step 2

Rewriting system is complete. See a, b | aabbbaaaab=a.