Morphocompletion for #3643 ⟨a, b | aabbabaaab=a

Solved by morph:4/1,3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbabaa ⇒ aaaababb
2. ababaaa ⇒ aaaabab
3. ababaaab ⇒ aabbabaa
4. aaaababbab ⇒ a
5. aabbabaaab ⇒ a
6. aaaababababbab ⇒ ababa
7. aaaabaababbaba ⇒ aaaab
8. aaaababaababbab ⇒ ababaa
9. aaaabababbabaa ⇒ aaaab
10. ababaaaabbabaa ⇒ aaaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aaa, [3/3] aab
Length 4:[4/0] abab, [4/1] baba, [4/2] abaa, [4/3] aaaa
Length 5:[5/0] aaaab, [5/1] babaa, [5/2] abbab, [5/3] ababa
Length 6:[6/0] aaaaba, [6/1] babbab, [6/2] ababaa, [6/3] bbabaa

Considering [length 4 / frequency 1] baba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cba ⇒ bac
2. baba ⇒ c
3. ccaac ⇒ ca
4. ccaab ⇒ cabca
5. acaac ⇒ aa
6. acaab ⇒ aabca
7. cabcaac ⇒ caba
8. cabcaab ⇒ c
9. ccaaa ⇒ caaac
10. aabcaac ⇒ aaba
11. aabcaab ⇒ a
12. acaaa ⇒ aaaac
13. caaabab ⇒ ccaa
14. caaabacb ⇒ cccaa
15. caaacbca ⇒ caaab
16. cabcaaa ⇒ cabaaac
17. aaaabab ⇒ acaa
18. aaaabacb ⇒ accaa
19. aaaacbca ⇒ aaaab
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ca, [2/2] ab, [2/3] ac, [2/4] ba, [2/5] cb, [2/6] bc
Length 3:[3/0] aaa, [3/1] caa, [3/2] aab, [3/3] aac, [3/4] bca, [3/5] aba, [3/6] aca
Length 4:[4/0] caaa, [4/1] caab, [4/2] caac, [4/3] aaaa, [4/4] acaa, [4/5] ccaa, [4/6] cabc
Length 5:[5/0] cabca, [5/1] abcaa, [5/2] aaaba, [5/3] aaaab, [5/4] caaab, [5/5] aabca, [5/6] aabab

Considering [length 3 / frequency 1] caa=d.

Step 3

Rewriting system is complete. See a, b | aabbabaaab=a.