Morphocompletion for #3634 ⟨a, b | aabbaabaab=b

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabbb ⇒ baabaab
2. aabbaabb ⇒ bbaabaab
3. aabbaabaab ⇒ b
4. aabbbaabaab ⇒ baaaabaabbb
5. aabaaaabaabbb ⇒ baabaabaabaab
6. aaaabaabbbaab ⇒ baaaaaabaabbb
7. bbaabaabaabaab ⇒ aabbb
8. aabbbbaabaab ⇒ bbaabaabaabb
9. aabbaaaabaabbb ⇒ baaaabaabaabbb
10. bbaabaaaaaabaabbb ⇒ aabaabbb
11. baabaabaabaabaabaab ⇒ aaaabaabbb
12. aabbbaaaabaabbb ⇒ bbaabb
13. aabbbbaaaaaabaabbb ⇒ bbaabbaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] bb, [2/3] ba
Length 3:[3/0] aab, [3/1] baa, [3/2] aaa, [3/3] bbb, [3/4] aba, [3/5] abb, [3/6] bba
Length 4:[4/0] baab, [4/1] aabb, [4/2] aaba, [4/3] abaa, [4/4] abbb, [4/5] aaaa, [4/6] bbaa
Length 5:[5/0] abaab, [5/1] aabbb, [5/2] aabaa, [5/3] baaba, [5/4] bbaab, [5/5] aaaab, [5/6] baabb
Length 6:[6/0] aabaab, [6/1] baabaa, [6/2] baabbb, [6/3] bbaaba, [6/4] aaaaba, [6/5] abaabb, [6/6] aabbaa
Length 7:[7/0] baabaab, [7/1] abaabbb, [7/2] bbaabaa, [7/3] aaaabaa, [7/4] aabaabb, [7/5] aaabaab, [7/6] aabaaba

Considering [length 3 / frequency 0] aab=c.

Step 2

Rewriting system is complete. See a, b | aabbaabaab=b.