| Back: | ⟨a, b | aabbaabaab=b⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaaabbb ⇒ baabaab |
| 2. | aabbaabb ⇒ bbaabaab |
| 3. | aabbaabaab ⇒ b |
| 4. | aabbbaabaab ⇒ baaaabaabbb |
| 5. | aabaaaabaabbb ⇒ baabaabaabaab |
| 6. | aaaabaabbbaab ⇒ baaaaaabaabbb |
| 7. | bbaabaabaabaab ⇒ aabbb |
| 8. | aabbbbaabaab ⇒ bbaabaabaabb |
| 9. | aabbaaaabaabbb ⇒ baaaabaabaabbb |
| 10. | bbaabaaaaaabaabbb ⇒ aabaabbb |
| 11. | baabaabaabaabaabaab ⇒ aaaabaabbb |
| 12. | aabbbaaaabaabbb ⇒ bbaabb |
| 13. | aabbbbaaaaaabaabbb ⇒ bbaabbaab |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 68 | lf:58,lp:10,rf:36,rp:3 |
|---|---|---|---|
| [2/1] | ab | 46 | lf:40,ls:6,rf:26,rs:4 |
| [2/2] | bb | 39 | lf:30,lp:2,ls:7,rf:19,rp:4,rs:8,lsrp:3,lprs:2,lsrs:3 |
| [2/3] | ba | 31 | lf:30,lp:1,rf:23,rp:5 |
| [3/0] | aab | 54 | lf:40,lp:8,ls:6,rf:26,rp:2,rs:4,lsrp:1,lprs:3 |
| [3/1] | baa | 31 | lf:30,lp:1,rf:23,rp:5 |
| [3/2] | aaa | 20 | lf:18,lp:2,rf:10,rp:1,a:4 |
| [3/3] | bbb | 19 | lf:13,ls:6,rf:6,rs:6,lsrs:2,a:2 |
| [3/4] | aba | 19 | lf:19,rf:13 |
| [3/5] | abb | 16 | lf:15,ls:1,rf:9,rs:2 |
| [3/6] | bba | 12 | lf:10,lp:2,rf:5,rp:4 |
| [4/0] | baab | 32 | lf:25,lp:1,ls:6,rf:20,rp:2,rs:4 |
| [4/1] | aabb | 23 | lf:15,lp:7,ls:1,rf:9,rp:1,rs:2,lprs:2 |
| [4/2] | aaba | 20 | lf:19,lp:1,rf:13,rp:1 |
| [4/3] | abaa | 19 | lf:19,rf:13 |
| [4/4] | abbb | 17 | lf:11,ls:6,rf:6,rs:6,lsrs:2,a:2 |
| [4/5] | aaaa | 13 | lf:11,lp:2,rf:6,rp:1,a:4 |
| [4/6] | bbaa | 12 | lf:10,lp:2,rf:5,rp:4 |
| [5/0] | abaab | 22 | lf:17,ls:5,rf:13,rs:3 |
| [5/1] | aabbb | 21 | lf:11,lp:4,ls:6,rf:6,rp:1,rs:6,re:1,lprs:1,lsrs:2,a:2 |
| [5/2] | aabaa | 20 | lf:19,lp:1,rf:13,rp:1 |
| [5/3] | baaba | 13 | lf:12,lp:1,rf:8,rp:2 |
| [5/4] | bbaab | 10 | lf:7,lp:2,ls:1,rf:5,rp:4,rs:1 |
| [5/5] | aaaab | 9 | lf:7,lp:2,rf:4,rp:1,a:4 |
| [5/6] | baabb | 8 | lf:7,ls:1,rf:8,rs:2,a:1 |
| [6/0] | aabaab | 22 | lf:17,ls:5,rf:13,rp:1,rs:3 |
| [6/1] | baabaa | 13 | lf:12,lp:1,rf:8,rp:2 |
| [6/2] | baabbb | 11 | lf:6,ls:5,rf:5,rs:5,lsrs:2,a:6 |
| [6/3] | bbaaba | 7 | lf:5,lp:2,rf:2,rp:2 |
| [6/4] | aaaaba | 7 | lf:6,lp:1,rf:4,rp:1,a:6 |
| [6/5] | abaabb | 6 | lf:6,rf:6,rs:1,a:3 |
| [6/6] | aabbaa | 6 | lf:3,lp:3,rf:1 |
| [7/0] | baabaab | 17 | lf:11,lp:1,ls:5,rf:8,rp:2,rs:3,re:1 |
| [7/1] | abaabbb | 11 | lf:6,ls:5,rf:5,rs:5,lsrs:2,a:6 |
| [7/2] | bbaabaa | 7 | lf:5,lp:2,rf:2,rp:2 |
| [7/3] | aaaabaa | 7 | lf:6,lp:1,rf:4,rp:1,a:6 |
| [7/4] | aabaabb | 6 | lf:6,rf:6,rp:1,rs:1,a:3 |
| [7/5] | aaabaab | 6 | lf:6,rf:4,a:6 |
| [7/6] | aabaaba | 6 | lf:6,rf:4,a:2 |
Considering [length 3 / frequency 0] aab=c.
Rewriting system is complete. See ⟨a, b | aabbaabaab=b⟩.