Morphocompletion for #3626 ⟨a, b | aabbaaaaba=b

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. babbaaaaba ⇒ aabbaaaabb
2. aabbaaaaba ⇒ b
3. bbbaaaabaaaaaba ⇒ aabbaaaaaabbaab
4. babbaaaaaabbaaaabb ⇒ aabbaaaabbbbaaaaba
5. aabbaaaaaabbaaaabb ⇒ bbbaaaaba
6. bbbaaaabaaaaaaabbaaaabb ⇒ aabbaaaaaabbaabbbaaaaba
7. bbbaaaababaaaabaaaaababaaaaba ⇒ aabbaaaaaabbaaaaaabbaaaaaabbb
8. babbaaaaaabbaaaaaabbaaaaaabbaab ⇒ aabbaaaabbbbaaaababaaaabaaaaaba
9. aabbaaaaaabbaaaaaabbaaaaaabbaab ⇒ bbbaaaababaaaabaaaaaba
10. bbbaaaabaaaaaaabbaaaaaabbaaaaaabbaab ⇒ aabbaaaaaabbaabbbaaaababaaaabaaaaaba
11. bbbaaaababaaaabaaaaababaaaaaabbaaaabb ⇒ aabbaaaaaabbaaaaaabbaaaaaabbbbbaaaaba
12. babbaaaaaabbaaaaaabbaaaaaabbaaaaaabbaaaaaabbb ⇒ aabbaaaabbbbaaaababaaaababaaaabaaaaababaaaaba
13. aabbaaaaaabbaaaaaabbaaaaaabbaaaaaabbaaaaaabbb ⇒ bbbaaaababaaaababaaaabaaaaababaaaaba
14. bbbaaaabaaaaaaabbaaaaaabbaaaaaabbaaaaaabbaaaaaabbb ⇒ aabbaaaaaabbaabbbaaaababaaaababaaaabaaaaababaaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] bb, [2/3] ab
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] abb, [3/4] bba, [3/5] aba, [3/6] bbb
Length 4:[4/0] aaaa, [4/1] baaa, [4/2] aaab, [4/3] aabb, [4/4] bbaa, [4/5] abba, [4/6] aaba
Length 5:[5/0] aaaaa, [5/1] baaaa, [5/2] aaaab, [5/3] bbaaa, [5/4] aaabb, [5/5] abbaa, [5/6] aabba
Length 6:[6/0] bbaaaa, [6/1] aaaabb, [6/2] aabbaa, [6/3] aaaaaa, [6/4] baaaaa, [6/5] aaaaab, [6/6] abbaaa
Length 7:[7/0] abbaaaa, [7/1] aabbaaa, [7/2] baaaaaa, [7/3] aaaaaab, [7/4] aaaaabb, [7/5] aaabbaa, [7/6] aaaabba

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See a, b | aabbaaaaba=b.