| Back: | ⟨a, b | aababbaaab=a⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aabbaa ⇒ abaaab |
| 2. | abaaababa ⇒ aaaababab |
| 3. | aababbaa ⇒ abaaabab |
| 4. | aaaabababb ⇒ a |
| 5. | abaaabbbaa ⇒ aabbabaaab |
| 6. | aaaabbabbaa ⇒ aaaabbbaaab |
| 7. | aaaabaabababba ⇒ aaaab |
| 8. | abaaabaabababb ⇒ aabba |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 32 | lf:23,lp:5,ls:4,rf:19,rp:5,lprp:2,lsrp:2,a:1 |
|---|---|---|---|
| [2/1] | ab | 25 | lf:22,lp:3,rf:15,rp:2,rs:6,lprs:2,a:1 |
| [2/2] | ba | 22 | lf:20,ls:2,rf:9,rs:1,a:1 |
| [2/3] | bb | 11 | lf:9,ls:2,rf:4,a:1 |
| [3/0] | aba | 18 | lf:14,lp:3,ls:1,rf:6,rp:2,a:1 |
| [3/1] | baa | 13 | lf:9,ls:4,rf:4,a:1 |
| [3/2] | aab | 12 | lf:10,lp:2,rf:9,rp:2,rs:4,lprs:1,a:1 |
| [3/3] | aaa | 12 | lf:9,lp:3,rf:10,rp:3,lprp:2,a:1 |
| [3/4] | abb | 10 | lf:8,ls:2,rf:3,a:1 |
| [3/5] | bab | 9 | lf:9,rf:4,rs:2,a:1 |
| [3/6] | bba | 7 | lf:6,ls:1,rf:3,rs:1,a:1 |
| [4/0] | bbaa | 8 | lf:4,ls:4,rf:1,a:1 |
| [4/1] | abab | 8 | lf:8,rf:3,rs:2,a:1 |
| [4/2] | abaa | 8 | lf:5,lp:3,rf:3,rp:2,a:1 |
| [4/3] | aaba | 8 | lf:7,lp:1,rf:2,a:1 |
| [4/4] | babb | 7 | lf:5,ls:2,a:1 |
| [4/5] | abba | 6 | lf:5,ls:1,rf:2,rs:1,a:1 |
| [4/6] | aaab | 6 | lf:6,rf:7,rs:4,a:1 |
| [5/0] | ababb | 6 | lf:4,ls:2,a:1 |
| [5/1] | abbaa | 6 | lf:3,ls:3,a:1 |
| [5/2] | aabab | 6 | lf:5,lp:1,rf:2,rs:1,lprs:1,a:1 |
| [5/3] | abaaa | 6 | lf:3,lp:3,rf:3,rp:2,a:1 |
| [5/4] | aaaab | 6 | lf:3,lp:3,rf:3,rp:3,rs:1,re:1,lprp:2,lprs:1,a:6 |
| [5/5] | ababa | 5 | lf:4,ls:1,rf:1,a:6 |
| [5/6] | babba | 4 | lf:3,ls:1,a:1 |
| [6/0] | abaaab | 6 | lf:3,lp:3,rf:3,rp:2,rs:2,re:1,lprs:1,a:1 |
| [6/1] | bababb | 5 | lf:3,ls:2,a:24 |
| [6/2] | aababa | 5 | lf:4,ls:1,rf:1,a:6 |
| [6/3] | babbaa | 4 | lf:2,ls:2,a:1 |
| [6/4] | aaaaba | 4 | lf:2,lp:2,rf:1,rp:1,a:6 |
| [6/5] | ababba | 3 | lf:2,ls:1,a:1 |
| [6/6] | ababab | 3 | lf:3,rf:1,rs:1,a:6 |
| [7/0] | abababb | 5 | lf:3,ls:2,a:24 |
| [7/1] | abaaaba | 4 | lf:2,lp:2,rf:1,rp:1,a:1 |
| [7/2] | aababab | 3 | lf:3,rf:1,rs:1,a:6 |
| [7/3] | aaababa | 3 | lf:2,ls:1,rf:1,a:6 |
| [7/4] | bbabbaa | 2 | lf:1,ls:1,a:32 |
| [7/5] | bababba | 2 | lf:1,ls:1,a:35 |
| [7/6] | ababbaa | 2 | lf:1,ls:1,a:1 |
Considering [length 5 / frequency 0] ababb=c.
Rewriting system is complete. See ⟨a, b | aababbaaab=a⟩.