Morphocompletion for #3601 ⟨a, b | aababbaaab=a⟩

Back:⟨a, b | aababbaaab=a⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbaa ⇒ abaaab
2. abaaababa ⇒ aaaababab
3. aababbaa ⇒ abaaabab
4. aaaabababb ⇒ a
5. abaaabbbaa ⇒ aabbabaaab
6. aaaabbabbaa ⇒ aaaabbbaaab
7. aaaabaabababba ⇒ aaaab
8. abaaabaabababb ⇒ aabba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] aaa, [3/4] abb, [3/5] bab, [3/6] bba
Length 4:[4/0] bbaa, [4/1] abab, [4/2] abaa, [4/3] aaba, [4/4] babb, [4/5] abba, [4/6] aaab
Length 5:[5/0] ababb, [5/1] abbaa, [5/2] aabab, [5/3] abaaa, [5/4] aaaab, [5/5] ababa, [5/6] babba
Length 6:[6/0] abaaab, [6/1] bababb, [6/2] aababa, [6/3] babbaa, [6/4] aaaaba, [6/5] ababba, [6/6] ababab
Length 7:[7/0] abababb, [7/1] abaaaba, [7/2] aababab, [7/3] aaababa, [7/4] bbabbaa, [7/5] bababba, [7/6] ababbaa

Considering [length 5 / frequency 0] ababb=c.

Step 2

Rewriting system is complete. See ⟨a, b | aababbaaab=a⟩.