| Back: | ⟨a, b | aabaababaa=a⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aababaa ⇒ abaaaba |
| 2. | abaaabaa ⇒ aaabaaba |
| 3. | ababaaa ⇒ aabaaba |
| 4. | aaabaababa ⇒ a |
| 5. | aaabababaa ⇒ abaaaababa |
| 6. | aaabaabaabaa ⇒ abaaaaabaaba |
| 7. | aaaababababaa ⇒ abaaaaabababa |
| 8. | aabaabababaa ⇒ ababaabaaaba |
| 9. | aabaabaabaababa ⇒ ababaa |
| 10. | aabababaabaaaba ⇒ ababaabaaaababa |
| 11. | aabaababababaa ⇒ abaabaabaababa |
| 12. | abaaaababababaa ⇒ aabaabaaabababa |
| 13. | aabababaabaaaababa ⇒ ababaabaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 64 | lf:45,lp:10,ls:9,rf:36,rp:3,rs:2,lsrp:3,lprs:2,a:2 |
|---|---|---|---|
| [2/1] | ba | 53 | lf:49,ls:4,rf:40,rs:10,lsrs:1,a:2 |
| [2/2] | ab | 52 | lf:49,lp:3,rf:40,rp:9,a:2 |
| [3/0] | aba | 56 | lf:49,lp:3,ls:4,rf:40,rp:9,rs:10,lsrp:3,lprs:3,lsrs:1,a:2 |
| [3/1] | baa | 31 | lf:23,ls:8,rf:19,rs:2,a:2 |
| [3/2] | aab | 30 | lf:24,lp:6,rf:20,rp:2,a:2 |
| [3/3] | bab | 22 | lf:22,rf:11,a:2 |
| [3/4] | aaa | 17 | lf:12,lp:4,ls:1,rf:14,rp:1,a:5 |
| [4/0] | abaa | 33 | lf:23,lp:2,ls:8,rf:19,rp:5,rs:2,lsrp:5,a:2 |
| [4/1] | aaba | 31 | lf:24,lp:6,ls:1,rf:20,rp:2,rs:5,lprs:2,a:2 |
| [4/2] | baba | 25 | lf:22,ls:3,rf:11,rs:5,a:2 |
| [4/3] | abab | 23 | lf:22,lp:1,rf:11,rp:4,a:2 |
| [4/4] | aaab | 11 | lf:8,lp:3,rf:8,rp:1,a:10 |
| [4/5] | baab | 10 | lf:10,rf:10,a:2 |
| [4/6] | baaa | 6 | lf:5,ls:1,rf:7,a:5 |
| [5/0] | ababa | 26 | lf:22,lp:1,ls:3,rf:11,rp:4,rs:5,lsrp:2,a:2 |
| [5/1] | aabaa | 17 | lf:12,lp:3,ls:2,rf:10,rp:2,rs:1,a:2 |
| [5/2] | babaa | 15 | lf:9,ls:6,rf:4,rs:1,a:2 |
| [5/3] | aabab | 14 | lf:11,lp:3,rf:5,a:2 |
| [5/4] | aaaba | 12 | lf:8,lp:3,ls:1,rf:8,rp:1,rs:2,a:10 |
| [5/5] | babab | 10 | lf:10,rf:2,a:3 |
| [5/6] | baaba | 10 | lf:10,rf:10,rs:3,a:2 |
| [6/0] | aababa | 17 | lf:11,lp:3,ls:3,rf:5,rs:3,lprs:1,a:2 |
| [6/1] | ababaa | 16 | lf:9,lp:1,ls:6,rf:4,rp:4,rs:1,re:1,lsrp:1,a:2 |
| [6/2] | aabaab | 11 | lf:8,lp:3,rf:6,rp:2,a:2 |
| [6/3] | bababa | 10 | lf:10,rf:2,rs:2,a:3 |
| [6/4] | ababab | 10 | lf:10,rf:2,a:3 |
| [6/5] | abaaba | 10 | lf:10,rf:10,rp:1,rs:3,a:2 |
| [6/6] | baabaa | 7 | lf:6,ls:1,rf:6,rs:1,a:2 |
| [7/0] | bababaa | 12 | lf:7,ls:5,a:3 |
| [7/1] | aabaaba | 11 | lf:8,lp:3,rf:6,rp:2,rs:3,re:1,a:2 |
| [7/2] | abababa | 10 | lf:10,rf:2,rs:2,a:3 |
| [7/3] | aababab | 9 | lf:7,lp:2,rf:2,a:3 |
| [7/4] | abaabaa | 7 | lf:6,ls:1,rf:6,rp:1,rs:1,a:2 |
| [7/5] | baababa | 6 | lf:4,ls:2,rf:1,rs:1,a:2 |
| [7/6] | aaababa | 6 | lf:4,lp:1,ls:1,rf:4,rs:2,lprs:1,a:22 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | aabaababaa=a⟩.