Morphocompletion for #3563 ⟨a, b | aabaababaa=a

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aababaa ⇒ abaaaba
2. abaaabaa ⇒ aaabaaba
3. ababaaa ⇒ aabaaba
4. aaabaababa ⇒ a
5. aaabababaa ⇒ abaaaababa
6. aaabaabaabaa ⇒ abaaaaabaaba
7. aaaababababaa ⇒ abaaaaabababa
8. aabaabababaa ⇒ ababaabaaaba
9. aabaabaabaababa ⇒ ababaa
10. aabababaabaaaba ⇒ ababaabaaaababa
11. aabaababababaa ⇒ abaabaabaababa
12. abaaaababababaa ⇒ aabaabaaabababa
13. aabababaabaaaababa ⇒ ababaabaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] bab, [3/4] aaa
Length 4:[4/0] abaa, [4/1] aaba, [4/2] baba, [4/3] abab, [4/4] aaab, [4/5] baab, [4/6] baaa
Length 5:[5/0] ababa, [5/1] aabaa, [5/2] babaa, [5/3] aabab, [5/4] aaaba, [5/5] babab, [5/6] baaba
Length 6:[6/0] aababa, [6/1] ababaa, [6/2] aabaab, [6/3] bababa, [6/4] ababab, [6/5] abaaba, [6/6] baabaa
Length 7:[7/0] bababaa, [7/1] aabaaba, [7/2] abababa, [7/3] aababab, [7/4] abaabaa, [7/5] baababa, [7/6] aaababa

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | aabaababaa=a.