Morphocompletion for #3557 ⟨a, b | aabaabaaab=a

Solved by morph:3/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaabab ⇒ aabaaba
2. aabaaaab ⇒ aaaabbaa
3. aaabaaab ⇒ aabaabaa
4. aabaabaaab ⇒ a
5. aaaabbaaab ⇒ aabaabaaba
6. aaaabaabab ⇒ aaaabbaaba
7. aaaabbaaaab ⇒ aaaabaabbaa
8. aabaabaaaaab ⇒ aaabaabaabaa
9. aaaabbaaaaab ⇒ aabaaabaabaa
10. aaaabbaabaaab ⇒ aabaabaabaaba
11. aaaabaabbaaab ⇒ aaaabbaabaaba
12. aabaabaabaabaa ⇒ aaaab
13. aabaabaaaaaab ⇒ aaabaaaaabbaa
14. aaaabbaaaaaab ⇒ aabaaaaaabbaa
15. aaaabbaabaaaaab ⇒ aaabaa
16. aaaabaabbaaaaab ⇒ aabaaa
17. aaaabbaabaabaabaa ⇒ aaaabaab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] aba, [3/4] abb, [3/5] bba, [3/6] bab
Length 4:[4/0] aaab, [4/1] aaaa, [4/2] aaba, [4/3] abaa, [4/4] baab, [4/5] baaa, [4/6] aabb
Length 5:[5/0] aaaab, [5/1] aabaa, [5/2] baaba, [5/3] abaab, [5/4] baaab, [5/5] aabba, [5/6] abbaa
Length 6:[6/0] aabaab, [6/1] aaaabb, [6/2] baabaa, [6/3] aaaaab, [6/4] abaaba, [6/5] aabbaa, [6/6] aaaaba
Length 7:[7/0] aaaabba, [7/1] aabaaba, [7/2] abaabaa, [7/3] baaaaab, [7/4] aaabbaa, [7/5] aaaabaa, [7/6] aabaaab

Considering [length 3 / frequency 1] aab=c.

Step 2

Rewriting system is complete. See a, b | aabaabaaab=a.