Morphocompletion for #3536 ⟨a, b | aabaaaaaba=b

Solved by morph:2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabaaab ⇒ baaaaba
2. aabaaaaabb ⇒ babaaaaaba
3. aabaaaaaba ⇒ b
4. baaaabaaaab ⇒ aababaaaaba
5. baaaaaababaab ⇒ aababbaaaabaa
6. baaaaaababbaab ⇒ aababbbaaaabaa
7. baaaaaababbbaab ⇒ aababbbbaaaabaa
8. baaaaaababbbbaab ⇒ aababbbbbaaaabaa
9. aabaaaaaaabab ⇒ baaabaaaaaaba
10. baaaabaaaaaabb ⇒ aabababaaaaaba
11. baaaabaaaaaaba ⇒ aabab
12. baaaaaababbaaaabaa ⇒ aababbaab
13. baaaaaababbbaaaabaa ⇒ aababbbaab
14. baaaaaababbbbaaaabaa ⇒ aababbbbaab
15. aababaaaabaaaaaaaba ⇒ baaaaaabab
16. aababbaaaabaaaaaaaba ⇒ baaaaaababb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aaa, [3/1] aab, [3/2] baa, [3/3] aba, [3/4] abb, [3/5] bab, [3/6] bba
Length 4:[4/0] aaaa, [4/1] aaba, [4/2] baaa, [4/3] aaab, [4/4] abaa, [4/5] abab, [4/6] baab
Length 5:[5/0] baaaa, [5/1] aaaaa, [5/2] aaaab, [5/3] aaaba, [5/4] aabaa, [5/5] aabab, [5/6] abaaa
Length 6:[6/0] aaaaba, [6/1] baaaaa, [6/2] aaaaaa, [6/3] aaaaab, [6/4] aabaaa, [6/5] baaaab, [6/6] aaabaa
Length 7:[7/0] baaaaaa, [7/1] aaaaaba, [7/2] aaaaaab, [7/3] aaaabaa, [7/4] aabaaaa, [7/5] baaaaba, [7/6] aaaabab

Considering [length 2 / frequency 0] aa=c.

Step 2

Rewriting system is complete. See a, b | aabaaaaaba=b.