Morphocompletion for #3535 ⟨a, b | aabaaaaaba=a

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. abaaaa ⇒ aaaaba
2. aaaaabaaba ⇒ a
3. abaabaa ⇒ aabaaba
4. aaaaaaababaaba ⇒ abaaa
5. aaaabaaabaaba ⇒ abaa
6. aabaababaa ⇒ abaaabaaba
7. abaababaaa ⇒ aaababaaba
8. aaaaaaabababaaba ⇒ ababaaa
9. aaaaaaabaaababaaba ⇒ abaaabaaa
10. aaaababaaabaaba ⇒ ababaa
11. aaaabaaabaaabaaba ⇒ abaaabaa
12. aabaabababaa ⇒ ababaaabaaba
13. aaaabababaaabaaba ⇒ abababaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab
Length 3:[3/0] aba, [3/1] aaa, [3/2] aab, [3/3] baa, [3/4] bab
Length 4:[4/0] aaba, [4/1] abaa, [4/2] aaaa, [4/3] aaab, [4/4] baab, [4/5] baba, [4/6] abab
Length 5:[5/0] baaba, [5/1] aabaa, [5/2] abaab, [5/3] aaaba, [5/4] aaaaa, [5/5] aaaab, [5/6] ababa
Length 6:[6/0] abaaba, [6/1] aaaaba, [6/2] ababaa, [6/3] aabaab, [6/4] aaabaa, [6/5] aaaaaa, [6/6] aababa
Length 7:[7/0] aabaaba, [7/1] babaaba, [7/2] aababaa, [7/3] abaaaba, [7/4] aaaabab, [7/5] aaaabaa, [7/6] aaaaaaa

Considering [length 5 / frequency 0] baaba=c.

Step 2

Rewriting system is complete. See a, b | aabaaaaaba=a.