Morphocompletion for #3501 ⟨a, b | aaabbabbaa=a⟩

Back:⟨a, b | aaabbabbaa=a⟩

Solved by morph:4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabba ⇒ abbaaaa
2. aabbabba ⇒ abbabbaa
3. abbabbaaaa ⇒ a
4. abbabbaabbaaaa ⇒ aabba
5. abbabbaaabbaaaa ⇒ aaabba
6. abbabbaabbaabbaaaa ⇒ aabbaabba
7. abbabbaabbaaabbaaaa ⇒ aabbaaabba
8. abbabbaaabbaabbaaaa ⇒ aaabbaabba
9. abbabbaaabbaaabbaaaa ⇒ aaabbaaabba
10. abbabbaabbaabbaabbaaaa ⇒ aabbaabbaabba
11. abbabbaabbaabbaaabbaaaa ⇒ aabbaabbaaabba
12. abbabbaabbaaabbaabbaaaa ⇒ aabbaaabbaabba
13. abbabbaaabbaabbaabbaaaa ⇒ aaabbaabbaabba
14. abbabbaabbaaabbaaabbaaaa ⇒ aabbaaabbaaabba
15. abbabbaaabbaabbaaabbaaaa ⇒ aaabbaabbaaabba
16. abbabbaaabbaaabbaabbaaaa ⇒ aaabbaaabbaabba
17. abbabbaaabbaaabbaaabbaaaa ⇒ aaabbaaabbaaabba
18. abbabbaabbaabbaabbaabbaaaa ⇒ aabbaabbaabbaabba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] abb, [3/1] bba, [3/2] aaa, [3/3] baa, [3/4] aab, [3/5] bab
Length 4:[4/0] abba, [4/1] bbaa, [4/2] aabb, [4/3] aaaa, [4/4] baaa, [4/5] baab, [4/6] aaab
Length 5:[5/0] abbaa, [5/1] aabba, [5/2] abbab, [5/3] bbaaa, [5/4] baaaa, [5/5] baabb, [5/6] bbaab
Length 6:[6/0] aabbaa, [6/1] abbaaa, [6/2] abbabb, [6/3] bbaaaa, [6/4] abbaab, [6/5] baabba, [6/6] bbaabb
Length 7:[7/0] abbabba, [7/1] abbaaaa, [7/2] aabbaaa, [7/3] abbaabb, [7/4] baabbaa, [7/5] bbaabba, [7/6] aaabbaa

Considering [length 4 / frequency 0] abba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabbabbaa=a⟩.