Morphocompletion for #3482 ⟨a, b | aaabbaaaab=a⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#	Rule
1.	aaabbaa ⇒ abaaaab
2.	aaaaabaab ⇒ abaaaabaa
3.	abaaaabaab ⇒ a
4.	aaabbabaaaab ⇒ abaaaababbaa
5.	aaaaabaaabaab ⇒ aaaaababbaaaa
6.	abaaaabaaabaab ⇒ abaaaababbaaaa
7.	aaaaababbaaaab ⇒ abaaaabaaaabba
8.	abaaaababbaaaab ⇒ aaabba
9.	aaabbabaabaaaab ⇒ abaaaababbaabaa
10.	aaaaababbaabaaaab ⇒ abaaaabaaaabbabaa
11.	aaaaabaaabaaabaab ⇒ aaaaabaaababbaaaa
12.	abaaaababbaabaaaab ⇒ aaabbabaa
13.	abaaaabaaabaaabaab ⇒ abaaaabaaababbaaaa
14.	aaabbabaabaabaaaab ⇒ abaaaababbaabaabaa
15.	aaaaabaaababbaaaab ⇒ aaaaababbaaaaaabba
16.	abaaaabaaababbaaaab ⇒ abaaaababbaaaaaabba
17.	aaaaababbaabaabaaaab ⇒ abaaaabaaaabbabaabaa
18.	abaaaababbaabaabaaaab ⇒ aaabbabaabaa
19.	abaaaababbaabaabaabaaaab ⇒ aaabbabaabaabaa
	...

Collecting factors up to length 8, frequency 7:

Length 2:	[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:	[3/0] aaa, [3/1] aab, [3/2] aba, [3/3] baa, [3/4] abb, [3/5] bba, [3/6] bab
Length 4:	[4/0] aaab, [4/1] abaa, [4/2] aaaa, [4/3] aaba, [4/4] baaa, [4/5] baab, [4/6] abba
Length 5:	[5/0] aaaab, [5/1] abaaa, [5/2] aabaa, [5/3] aaaba, [5/4] baaaa, [5/5] abaab, [5/6] aaaaa
Length 6:	[6/0] baaaab, [6/1] abaaaa, [6/2] aabaab, [6/3] aaaaba, [6/4] aabaaa, [6/5] aaaaab, [6/6] aaabaa
Length 7:	[7/0] abaaaab, [7/1] aaaaaba, [7/2] aaabaab, [7/3] aaababb, [7/4] aababba, [7/5] ababbaa, [7/6] aaaabaa

Considering [length 5 / frequency 0] aaaab=c.

Reduction order:
- Left-to-right recursive path with deg(c) = 0; deg(b) = deg(a) = 1, b < a
Auxiliary generators:
1. aaaab=c

Rewriting system is complete. See ⟨a, b | aaabbaaaab=a⟩.