Morphocompletion for #3461 ⟨a, b | aaabababaa=a

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaba ⇒ abaaaa
2. aabababa ⇒ abababaa
3. abababaaaa ⇒ a
4. abababaabaaaa ⇒ aaba
5. abababaaabaaaa ⇒ aaaba
6. abababaababaaaa ⇒ aababa
7. abababaabaabaaaa ⇒ aabaaba
8. abababaaababaaaa ⇒ aaababa
9. abababaabaaabaaaa ⇒ aabaaaba
10. abababaaabaabaaaa ⇒ aaabaaba
11. abababaababaabaaaa ⇒ aababaaba
12. abababaabaababaaaa ⇒ aabaababa
13. abababaaabaaabaaaa ⇒ aaabaaaba
14. abababaababaaabaaaa ⇒ aababaaaba
15. abababaabaabaabaaaa ⇒ aabaabaaba
16. abababaabaaababaaaa ⇒ aabaaababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa, [3/3] bab, [3/4] aab
Length 4:[4/0] abab, [4/1] abaa, [4/2] baba, [4/3] aaaa, [4/4] aaba, [4/5] baaa, [4/6] baab
Length 5:[5/0] ababa, [5/1] baaaa, [5/2] abaaa, [5/3] babaa, [5/4] aabaa, [5/5] abaab, [5/6] baaba
Length 6:[6/0] ababab, [6/1] abaaaa, [6/2] ababaa, [6/3] bababa, [6/4] abaaba, [6/5] aabaaa, [6/6] baabaa
Length 7:[7/0] abababa, [7/1] aabaaaa, [7/2] bababaa, [7/3] abaabaa, [7/4] ababaaa, [7/5] ababaab, [7/6] babaaaa

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See a, b | aaabababaa=a.