Morphocompletion for #3461 ⟨a, b | aaabababaa=a⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaba ⇒ abaaaa
2. aabababa ⇒ abababaa
3. abababaaaa ⇒ a
4. abababaabaaaa ⇒ aaba
5. abababaaabaaaa ⇒ aaaba
6. abababaababaaaa ⇒ aababa
7. abababaabaabaaaa ⇒ aabaaba
8. abababaaababaaaa ⇒ aaababa
9. abababaabaaabaaaa ⇒ aabaaaba
10. abababaaabaabaaaa ⇒ aaabaaba
11. abababaababaabaaaa ⇒ aababaaba
12. abababaabaababaaaa ⇒ aabaababa
13. abababaaabaaabaaaa ⇒ aaabaaaba
14. abababaababaaabaaaa ⇒ aababaaaba
15. abababaabaabaabaaaa ⇒ aabaabaaba
16. abababaabaaababaaaa ⇒ aabaaababa
...

Collecting factors up to length 8 / frequency 7:

[2/0]aa93lf:77,lp:2,ls:14,rf:35,rp:13,rs:2,lsrp:13,lprs:2,a:2
[2/1]ab89lf:75,lp:14,rf:33,rp:2,a:2
[2/2]ba77lf:75,ls:2,rf:33,rs:13,a:2
[3/0]aba91lf:75,lp:14,ls:2,rf:33,rp:2,rs:13,lsrp:2,lprs:13,a:2
[3/1]aaa53lf:38,lp:1,ls:14,rf:10,rp:4,rs:1,lsrp:4,lprs:1,a:2
[3/2]baa37lf:37,rf:12,rs:1,a:2
[3/3]bab36lf:36,rf:8,a:2
[3/4]aab26lf:25,lp:1,rf:23,rp:9,a:3
[4/0]abab50lf:36,lp:14,rf:8,rp:1,a:2
[4/1]abaa37lf:37,rf:12,rp:1,rs:1,a:2
[4/2]baba37lf:36,ls:1,rf:8,rs:4,a:2
[4/3]aaaa30lf:15,lp:1,ls:14,rf:1,rs:1,lprs:1,a:2
[4/4]aaba27lf:25,lp:1,ls:1,rf:23,rp:9,rs:9,re:1,a:3
[4/5]baaa22lf:22,rf:5,a:2
[4/6]baab15lf:15,rf:6,a:7
[5/0]ababa51lf:36,lp:14,ls:1,rf:8,rp:1,rs:4,lsrp:1,lprs:4,a:2
[5/1]baaaa28lf:14,ls:14,rf:1,rs:1,a:2
[5/2]abaaa22lf:22,rf:5,rp:1,a:2
[5/3]babaa20lf:20,rf:3,rs:1,a:2
[5/4]aabaa17lf:17,rf:8,rp:5,a:5
[5/5]abaab15lf:15,rf:6,a:7
[5/6]baaba15lf:15,rf:6,rs:4,a:7
[6/0]ababab29lf:15,lp:14,rf:1,rp:1,a:2
[6/1]abaaaa28lf:14,ls:14,rf:1,rp:1,rs:1,re:1,a:2
[6/2]ababaa20lf:20,rf:3,rs:1,a:2
[6/3]bababa16lf:15,ls:1,rf:1,a:2
[6/4]abaaba15lf:15,rf:6,rs:4,a:7
[6/5]aabaaa12lf:12,rf:3,rp:2,a:5
[6/6]baabaa11lf:11,rf:1,a:7
[7/0]abababa30lf:15,lp:14,ls:1,rf:1,rp:1,lsrp:10,a:2
[7/1]aabaaaa18lf:9,ls:9,a:5
[7/2]bababaa14lf:14,rf:1,rs:1,a:2
[7/3]abaabaa11lf:11,rf:1,a:7
[7/4]ababaaa10lf:10,rf:1,a:2
[7/5]ababaab10lf:10,rf:1,a:7
[7/6]babaaaa10lf:5,ls:5,a:2

Considering [length 5 / frequency 0] ababa=c.

Step 2

Rewriting system is complete. See ⟨a, b | aaabababaa=a⟩.