Morphocompletion for #3382 ⟨a, b | aaaababaaa=a

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. ababaa ⇒ aababa
2. aababaa ⇒ aaababa
3. abaaaaaa ⇒ aaaaaaba
4. aaaaaababa ⇒ a
5. ababababaa ⇒ aababababa
6. aabababaababa ⇒ aabaababababa
7. aaaaaabaababa ⇒ abaa
8. ababaababababa ⇒ aababababababa
9. aaaaaabaaababa ⇒ abaaa
10. aaaaaabaaaababa ⇒ abaaaa
11. aaaaaabaabaababa ⇒ abaabaa
12. aaaaaabaaaaababa ⇒ abaaaaa
13. aaaaaaabaababababa ⇒ aabababaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab
Length 3:[3/0] aba, [3/1] aaa, [3/2] bab, [3/3] aab, [3/4] baa
Length 4:[4/0] aaaa, [4/1] baba, [4/2] abab, [4/3] aaba, [4/4] abaa, [4/5] aaab, [4/6] baab
Length 5:[5/0] ababa, [5/1] aaaaa, [5/2] aabab, [5/3] aaaba, [5/4] aaaab, [5/5] babaa, [5/6] aabaa
Length 6:[6/0] aababa, [6/1] aaaaaa, [6/2] aaaaba, [6/3] bababa, [6/4] aaaaab, [6/5] ababab, [6/6] ababaa
Length 7:[7/0] aaaaaab, [7/1] abababa, [7/2] aaaaaba, [7/3] aaababa, [7/4] baababa, [7/5] aaaabaa, [7/6] abaabab

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See a, b | aaaababaaa=a.