| Back: | ⟨a, b | aaaababaaa=a⟩ |
|---|
Solved by morph:3/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | ababaa ⇒ aababa |
| 2. | aababaa ⇒ aaababa |
| 3. | abaaaaaa ⇒ aaaaaaba |
| 4. | aaaaaababa ⇒ a |
| 5. | ababababaa ⇒ aababababa |
| 6. | aabababaababa ⇒ aabaababababa |
| 7. | aaaaaabaababa ⇒ abaa |
| 8. | ababaababababa ⇒ aababababababa |
| 9. | aaaaaabaaababa ⇒ abaaa |
| 10. | aaaaaabaaaababa ⇒ abaaaa |
| 11. | aaaaaabaabaababa ⇒ abaabaa |
| 12. | aaaaaabaaaaababa ⇒ abaaaaa |
| 13. | aaaaaaabaababababa ⇒ aabababaa |
| ... |
Collecting factors up to length 8 / frequency 7:
| [2/0] | aa | 74 | lf:61,lp:9,ls:4,rf:26,rp:7,rs:6,lprp:3,lsrp:4,lprs:6,a:4 |
|---|---|---|---|
| [2/1] | ba | 52 | lf:43,ls:9,rf:29,rs:6,lsrs:2,a:4 |
| [2/2] | ab | 47 | lf:43,lp:4,rf:29,rp:5,a:4 |
| [3/0] | aba | 56 | lf:43,lp:4,ls:9,rf:29,rp:5,rs:6,lsrp:5,lprs:4,lsrs:2,a:4 |
| [3/1] | aaa | 47 | lf:39,lp:7,ls:1,rf:11,rp:2,rs:3,lsrp:1,lprs:3,a:4 |
| [3/2] | bab | 21 | lf:21,rf:15,a:4 |
| [3/3] | aab | 20 | lf:18,lp:2,rf:9,rp:5,lprp:1,a:4 |
| [3/4] | baa | 16 | lf:13,ls:3,rf:8,rs:3,a:4 |
| [4/0] | aaaa | 36 | lf:28,lp:7,ls:1,rf:6,rp:1,rs:2,lsrp:1,lprs:2,a:13 |
| [4/1] | baba | 30 | lf:21,ls:9,rf:15,rs:5,lsrs:2,a:4 |
| [4/2] | abab | 24 | lf:21,lp:3,rf:15,a:4 |
| [4/3] | aaba | 20 | lf:18,lp:2,rf:9,rp:5,rs:1,lprp:1,a:4 |
| [4/4] | abaa | 17 | lf:13,lp:1,ls:3,rf:8,rp:5,rs:3,re:1,a:4 |
| [4/5] | aaab | 10 | lf:10,rf:2,rp:1,a:4 |
| [4/6] | baab | 6 | lf:6,rf:2,a:12 |
| [5/0] | ababa | 33 | lf:21,lp:3,ls:9,rf:15,rs:5,lprs:12,lsrs:2,a:4 |
| [5/1] | aaaaa | 26 | lf:18,lp:7,ls:1,rf:3,rp:1,rs:1,lsrp:1,lprs:1,a:13 |
| [5/2] | aabab | 13 | lf:11,lp:2,rf:6,rp:4,a:4 |
| [5/3] | aaaba | 10 | lf:10,rf:2,rp:1,rs:1,a:4 |
| [5/4] | aaaab | 9 | lf:9,rf:1,a:13 |
| [5/5] | babaa | 8 | lf:5,ls:3,rf:1,rs:1,a:4 |
| [5/6] | aabaa | 7 | lf:7,rf:2,rp:1,rs:1,a:13 |
| [6/0] | aababa | 20 | lf:11,lp:2,ls:7,rf:6,rp:4,rs:2,re:1,lprs:10,a:4 |
| [6/1] | aaaaaa | 17 | lf:9,lp:7,ls:1,rf:1,rp:1,lsrp:1,a:13 |
| [6/2] | aaaaba | 9 | lf:9,rf:1,rs:1,a:13 |
| [6/3] | bababa | 9 | lf:7,ls:2,rf:9,rs:3,lsrs:1,a:11 |
| [6/4] | aaaaab | 8 | lf:8,rf:1,a:13 |
| [6/5] | ababab | 8 | lf:7,lp:1,rf:9,a:11 |
| [6/6] | ababaa | 7 | lf:4,lp:1,ls:2,rf:1,rs:1,a:4 |
| [7/0] | aaaaaab | 13 | lf:7,lp:6,rf:1,rp:1,a:13 |
| [7/1] | abababa | 10 | lf:7,lp:1,ls:2,rf:9,rs:3,lprs:1,lsrs:1,a:11 |
| [7/2] | aaaaaba | 8 | lf:8,rf:1,rs:1,a:13 |
| [7/3] | aaababa | 8 | lf:4,ls:4,rf:1,rp:1,rs:1,re:1,a:4 |
| [7/4] | baababa | 8 | lf:5,ls:3,rf:1,a:12 |
| [7/5] | aaaabaa | 6 | lf:6,a:13 |
| [7/6] | abaabab | 5 | lf:5,rf:1,a:12 |
Considering [length 3 / frequency 0] aba=c.
Rewriting system is complete. See ⟨a, b | aaaababaaa=a⟩.