Morphocompletion for #3374 ⟨a, b | aaaabaabaa=a

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaaba ⇒ abaaaa
2. abaabaaaaa ⇒ a
3. aabaaba ⇒ abaabaa
4. abaababaaaaaaa ⇒ aaaba
5. abaabaaabaaaa ⇒ aaba
6. aababaabaa ⇒ abaabaaaba
7. aaababaaba ⇒ abaababaaa
8. abaabababaaaaaaa ⇒ aaababa
9. abaababaaabaaaaaaa ⇒ aaabaaaba
10. abaabaaababaaaa ⇒ aababa
11. abaabaaabaaabaaaa ⇒ aabaaaba
12. aabababaabaa ⇒ abaabaaababa
13. aaabababaaba ⇒ abaabababaaa
14. ababaabaaabaaabaaa ⇒ aababaaba
15. abaababababaaaaaaa ⇒ aaabababa
16. abaabaaabababaaaa ⇒ aabababa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa, [3/3] aab, [3/4] bab
Length 4:[4/0] abaa, [4/1] aaba, [4/2] aaaa, [4/3] baaa, [4/4] abab, [4/5] baba, [4/6] baab
Length 5:[5/0] abaab, [5/1] abaaa, [5/2] ababa, [5/3] baaba, [5/4] aabaa, [5/5] aaaaa, [5/6] aaaba
Length 6:[6/0] abaaba, [6/1] aabaaa, [6/2] abaaaa, [6/3] aababa, [6/4] ababaa, [6/5] aaaaaa, [6/6] baabaa
Length 7:[7/0] abaabaa, [7/1] abaabab, [7/2] abaaaba, [7/3] aaaaaaa, [7/4] babaaba, [7/5] aabaaab, [7/6] babaaaa

Considering [length 5 / frequency 0] abaab=c.

Step 2

Rewriting system is complete. See a, b | aaaabaabaa=a.