| Back: | ⟨a, b | aaaabaabaa=a⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | aaaaba ⇒ abaaaa |
| 2. | abaabaaaaa ⇒ a |
| 3. | aabaaba ⇒ abaabaa |
| 4. | abaababaaaaaaa ⇒ aaaba |
| 5. | abaabaaabaaaa ⇒ aaba |
| 6. | aababaabaa ⇒ abaabaaaba |
| 7. | aaababaaba ⇒ abaababaaa |
| 8. | abaabababaaaaaaa ⇒ aaababa |
| 9. | abaababaaabaaaaaaa ⇒ aaabaaaba |
| 10. | abaabaaababaaaa ⇒ aababa |
| 11. | abaabaaabaaabaaaa ⇒ aabaaaba |
| 12. | aabababaabaa ⇒ abaabaaababa |
| 13. | aaabababaaba ⇒ abaabababaaa |
| 14. | ababaabaaabaaabaaa ⇒ aababaaba |
| 15. | abaababababaaaaaaa ⇒ aaabababa |
| 16. | abaabaaabababaaaa ⇒ aabababa |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] aa, [2/1] ab, [2/2] ba |
|---|---|
| Length 3: | [3/0] aba, [3/1] aaa, [3/2] baa, [3/3] aab, [3/4] bab |
| Length 4: | [4/0] abaa, [4/1] aaba, [4/2] aaaa, [4/3] baaa, [4/4] abab, [4/5] baba, [4/6] baab |
| Length 5: | [5/0] abaab, [5/1] abaaa, [5/2] ababa, [5/3] baaba, [5/4] aabaa, [5/5] aaaaa, [5/6] aaaba |
| Length 6: | [6/0] abaaba, [6/1] aabaaa, [6/2] abaaaa, [6/3] aababa, [6/4] ababaa, [6/5] aaaaaa, [6/6] baabaa |
| Length 7: | [7/0] abaabaa, [7/1] abaabab, [7/2] abaaaba, [7/3] aaaaaaa, [7/4] babaaba, [7/5] aabaaab, [7/6] babaaaa |
Considering [length 5 / frequency 0] abaab=c.
Rewriting system is complete. See ⟨a, b | aaaabaabaa=a⟩.