Morphocompletion for #333 ⟨a, b | ababbaba=1⟩

Solved by morph:2/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. babaa ⇒ aabab
2. bbaba ⇒ ababb
3. baabab ⇒ ababba
4. aababbab ⇒ 1
5. baaaabab ⇒ ababbaaa
6. bbaaabab ⇒ ababbbaa
7. baaaaaabab ⇒ ababbaaaaa
8. baabaaabab ⇒ ababbaabaa
9. bbaaaaabab ⇒ ababbbaaaa
10. aababababbab ⇒ baba
11. baaaaaaaabab ⇒ ababbaaaaaaa
12. baaaabaaabab ⇒ ababbaaaabaa
13. baabaaaaabab ⇒ ababbaabaaaa
14. bbaaaaaaabab ⇒ ababbbaaaaaa
15. bbaaabaaabab ⇒ ababbbaaabaa
...

Collecting factors up to length 7 / frequency 4:

[2/0]aa51lf:48,lp:2,ls:1,rf:35,rp:1,rs:10,lsrp:1,a:5
[2/1]ab49lf:36,ls:13,rf:31,rp:12,rs:1,lsrp:11,a:1
[2/2]ba45lf:36,lp:8,ls:1,rf:30,rp:1,rs:2,lprs:1,a:1
[2/3]bb12lf:7,lp:5,rf:16,rs:1,lprs:1,a:1
[3/0]bab33lf:19,lp:1,ls:13,rf:14,rp:1,rs:1,lsrp:1,lprs:1,a:1
[3/1]aaa30lf:30,rf:20,rs:6,a:11
[3/2]baa24lf:16,lp:7,ls:1,rf:14,rs:4,lprs:2,a:8
[3/3]aba22lf:21,ls:1,rf:18,rp:12,rs:1,lsrp:1,a:1
[4/0]abab26lf:15,ls:11,rf:13,rp:12,rs:1,lsrp:11,a:1
[4/1]aaba19lf:17,lp:2,rf:5,rp:1,a:5
[4/2]aaaa18lf:18,rf:12,rs:5,a:12
[4/3]baaa16lf:12,lp:4,rf:8,rs:1,lprs:1,a:11
[5/0]aabab26lf:13,lp:2,ls:11,rf:1,rp:1,rs:1,re:1,a:5
[5/1]aaaba12lf:12,rf:2,a:11
[5/2]baaaa11lf:7,lp:4,rf:6,rs:2,a:12
[5/3]aaaaa11lf:11,rf:6,rs:3,a:15
[6/0]aaabab20lf:10,ls:10,a:11
[6/1]baaaaa7lf:5,lp:2,rf:3,rs:1,lprs:1,a:15
[6/2]aaaaba7lf:7,rf:1,a:12
[6/3]aaaaaa6lf:6,rf:3,rs:2,a:15

Considering [length 2 / frequency 0] aa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ca ⇒ ac
2. aa ⇒ c
3. cbab ⇒ babc
4. cbabc ⇒ babcc
5. cbaba ⇒ babac
6. cbabb ⇒ babcb
7. abcbab ⇒ abbabc
8. babcba ⇒ abcbab
9. bbaba ⇒ ababb
10. bbabcbc ⇒ a
11. cbbabcb ⇒ a
12. ababba ⇒ bbabc
13. abbabcb ⇒ 1
14. babbabc ⇒ 1
15. babbabcc ⇒ c
...

Collecting factors up to length 6 / frequency 7:

[2/0]ba26lf:19,lp:3,ls:4,rf:9,rp:4,lsrp:1,a:3
[2/1]ab23lf:18,lp:3,ls:2,rf:11,rp:3,rs:1,lprp:1,lsrp:1,a:3
[2/2]cb17lf:10,lp:5,ls:2,rf:2,rs:1,lprs:1,a:15
[2/3]bc12lf:9,ls:3,rf:6,rs:3,a:12
[2/4]bb11lf:8,lp:2,ls:1,rf:3,rp:1,rs:1,lprs:1,a:3
[2/5]cc2lf:1,ls:1,rf:1,rs:1,a:34
[2/6]ac0rf:2,rp:1,rs:2,re:1,a:2
[3/0]bab20lf:15,lp:3,ls:2,rf:8,rp:4,rs:1,lsrp:10,lprs:1,a:3
[3/1]cba11lf:6,lp:4,ls:1,rf:1,a:15
[3/2]abc11lf:8,lp:1,ls:2,rf:6,rp:1,rs:3,lprs:1,a:12
[3/3]bba10lf:7,lp:2,ls:1,rf:2,rp:1,lsrp:1,a:3
[3/4]abb7lf:5,lp:1,ls:1,rf:2,rp:1,rs:1,a:3
[3/5]bcb7lf:5,ls:2,rf:2,rs:1,a:15
[3/6]aba6lf:3,lp:1,ls:2,rf:2,rp:1,lsrp:1,a:3
[4/0]babc10lf:7,lp:1,ls:2,rf:5,rp:3,rs:3,re:1,lsrp:10,a:12
[4/1]bbab8lf:6,lp:2,rf:2,rp:1,a:3
[4/2]cbab8lf:4,lp:3,ls:1,rf:1,rs:1,a:15
[4/3]abcb8lf:5,lp:1,ls:2,rf:2,rp:1,rs:1,a:15
[4/4]babb7lf:4,lp:2,ls:1,rf:1,rs:1,a:3
[4/5]abba6lf:4,lp:1,ls:1,rf:1,rp:1,a:12
[4/6]baba4lf:2,ls:2,rf:1,rp:1,lsrp:10,a:3
[5/0]bbabc7lf:5,lp:1,ls:1,rf:2,rp:1,rs:2,re:1,a:12
[5/1]babcb7lf:4,lp:1,ls:2,rf:1,rp:1,rs:1,re:1,a:22
[5/2]babba6lf:3,lp:2,ls:1,a:12
[5/3]abbab4lf:3,lp:1,rf:1,rp:1,a:15
[5/4]abcba4lf:2,lp:1,ls:1,rf:1,rp:1,lsrp:10,a:15
[5/5]ababb2lf:1,lp:1,rf:1,rp:1,rs:1,re:1,a:3
[5/6]cbbab2lf:1,lp:1,a:28

Considering [length 3 / frequency 0] bab=d.

Step 3

Rewriting system is complete. See ⟨a, b | ababbaba=1⟩.