Morphocompletion for #331 ⟨a, b | abababba=1⟩

Solved by morph:2/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baab ⇒ abba
2. bbaab ⇒ babba
3. bbaaab ⇒ abbbaa
4. ababab ⇒ babbaa
5. baaabba ⇒ aabbbaa
6. bababbaa ⇒ 1
7. baabbabbaa ⇒ ab
8. baabbababba ⇒ abb
9. baaabbbabbaa ⇒ aabb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] baa, [3/1] bba, [3/2] bab, [3/3] aab
Length 4:[4/0] bbaa, [4/1] abba, [4/2] abab, [4/3] baab
Length 5:[5/0] baaab, [5/1] abbaa, [5/2] babab, [5/3] babba
Length 6:[6/0] babbaa, [6/1] baaabb, [6/2] baabba, [6/3] bababb

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caccc ⇒ a
2. cccbc ⇒ b
3. aaccc ⇒ cacca
4. ba ⇒ c
5. ccbca ⇒ 1
6. bcac ⇒ cbca
7. bccac ⇒ cbcca
8. accb ⇒ cbca
9. acccccb ⇒ bca
10. abc ⇒ cab
11. acbc ⇒ cacb
12. bccbc ⇒ cccbb
13. bcaa ⇒ acccccc
14. bcbca ⇒ cccb
15. bcab ⇒ cbc
16. bccab ⇒ cbcc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bc, [2/1] cc, [2/2] ac, [2/3] ca, [2/4] cb, [2/5] ab, [2/6] aa
Length 3:[3/0] bca, [3/1] ccc, [3/2] cbc, [3/3] ccb, [3/4] bcc, [3/5] acc, [3/6] cac
Length 4:[4/0] ccbc, [4/1] accc, [4/2] bcca, [4/3] cbca, [4/4] cccb, [4/5] bcbc, [4/6] bccb
Length 5:[5/0] ccccb, [5/1] acccc, [5/2] ccccc, [5/3] cccbb, [5/4] cbcca, [5/5] cacca

Considering [length 3 / frequency 0] bca=d.

Step 3

Rewriting system is complete. See a, b | abababba=1⟩.