Certificate for #3293 ⟨a, b | abbabbbabba=1⟩

Completion settings:

[1] abbabbbabba=1

Axiom: abbabbbabba=1.

Referenced by [4].

[2] abba=c

Axiom: abba=c.

Referenced by [4], [7], [9].

[3] bbb=d

Axiom: bbb=d.

Defines rule #7.

Referenced by [4], [6], [11].

[4] cdc=1

Overlap of [1] abbabbbabba=1 with [2] abba=c:

abbabbbabba abba

Critical pair: cbbbabba=1.

Reduce LHS:

[3]c(bbb)abba
[2]cd(abba)
cdc

Referenced by [5], [8], [10], [12].

[5] dc=cd

Overlap of [4] cdc=1 with [4] cdc=1:

cd c cdc

Critical pair: cd=dc.

Flip LHS and RHS.

Defines rule #1.

Referenced by [8], [12], [14], [16].

[6] db=bd

Overlap of [3] bbb=d with [3] bbb=d:

b bb bbb

Critical pair: bd=db.

Flip LHS and RHS.

Defines rule #3.

Referenced by [13].

[7] abbc=cbba

Overlap of [2] abba=c with [2] abba=c:

abb a abba

Critical pair: abbc=cbba.

Referenced by [8].

[8] abb=cbbacd

Overlap of [7] abbc=cbba with [4] cdc=1:

abb c cdc

Critical pair: abb=cbbadc.

Reduce RHS:

[5]cbba(dc)
cbbacd

Defines rule #8.

Referenced by [9].

[9] cbbacda=c

Overlap of [2] abba=c with [8] abb=cbbacd:

abba abb

Critical pair: cbbacda=c.

Referenced by [10].

[10] bbacda=1

Overlap of [4] cdc=1 with [9] cbbacda=c:

cd c cbbacda

Critical pair: cdc=bbacda.

Reduce LHS:

[4](cdc)
⇒ 1

Flip LHS and RHS.

Referenced by [11].

[11] dacda=b

Overlap of [3] bbb=d with [10] bbacda=1:

b bb bbacda

Critical pair: b=dacda.

Flip LHS and RHS.

Referenced by [15], [18].

[12] ccd=1

Overlap of [4] cdc=1 with [5] dc=cd:

c dc dc

Critical pair: ccd=1.

Defines rule #2.

Referenced by [13], [15], [16], [18].

[13] ccbd=b

Overlap of [12] ccd=1 with [6] db=bd:

cc d db

Critical pair: ccbd=b.

Referenced by [14].

[14] ccbcd=bc

Overlap of [13] ccbd=b with [5] dc=cd:

ccb d dc

Critical pair: ccbcd=bc.

Referenced by [16].

[15] acda=ccb

Overlap of [12] ccd=1 with [11] dacda=b:

cc d dacda

Critical pair: ccb=acda.

Flip LHS and RHS.

Referenced by [17].

[16] ccb=bcc

Overlap of [14] ccbcd=bc with [5] dc=cd:

ccbc d dc

Critical pair: ccbccd=bcc.

Reduce LHS:

[12]ccb(ccd)
ccb

Defines rule #4.

Referenced by [17].

[17] acda=bcc

Simplify [15] acda=ccb.

Reduce RHS:

[16](ccb)
bcc

Defines rule #6.

Referenced by [18].

[18] acb=bca

Overlap of [17] acda=bcc with [11] dacda=b:

ac da dacda

Critical pair: acb=bcccda.

Reduce RHS:

[12]bc(ccd)a
bca

Defines rule #5.