Morphocompletion for #3288 ⟨a, b | abbabababba=1⟩

Solved by morph:4/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. babbba ⇒ abbbab
2. bbabbba ⇒ babbbab
3. bababba ⇒ abbabab
4. bbaabbabab ⇒ abbabababb
5. aabbabababb ⇒ 1
6. aababbababbbba ⇒ bab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] bb, [2/2] ab, [2/3] aa
Length 3:[3/0] bba, [3/1] bab, [3/2] abb, [3/3] aba
Length 4:[4/0] babb, [4/1] abab, [4/2] baba, [4/3] bbba
Length 5:[5/0] babab, [5/1] ababb, [5/2] abbba, [5/3] babbb
Length 6:[6/0] bababb, [6/1] bbabab, [6/2] abbaba, [6/3] ababba

Considering [length 4 / frequency 0] babb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. ccb ⇒ bcc
2. abbcb ⇒ cc
3. cabbcb ⇒ ccc
4. cca ⇒ acc
5. ccca ⇒ cacc
6. babc ⇒ cabb
7. babb ⇒ c
8. cbcab ⇒ abcbc
9. bcba ⇒ cbab
10. abcbbab ⇒ cbca
11. cacac ⇒ acacc
12. bcaca ⇒ cacab
13. bbaca ⇒ cabab
14. acaacc ⇒ bbab
15. acaabcc ⇒ bc
16. abacacc ⇒ cb
17. cacaca ⇒ bbab
18. cabaca ⇒ b
19. aabbabac ⇒ 1
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ca, [2/1] ab, [2/2] ac, [2/3] cc, [2/4] ba, [2/5] bc, [2/6] cb
Length 3:[3/0] aca, [3/1] cac, [3/2] bab, [3/3] bcb, [3/4] cab, [3/5] abb, [3/6] bac
Length 4:[4/0] caca, [4/1] baca, [4/2] abac, [4/3] acaa, [4/4] acac, [4/5] bbcb, [4/6] bbab
Length 5:[5/0] abaca, [5/1] acaca, [5/2] acaab, [5/3] acaac, [5/4] aabba, [5/5] babac, [5/6] cabac

Considering [length 3 / frequency 0] aca=d.

Step 3

Rewriting system is complete. See a, b | abbabababba=1⟩.