Morphocompletion for #3277 ⟨a, b | abbaabaaaab=1⟩

Solved by morph:5/0,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaabaaa ⇒ baabaaaab
2. abaaaabab ⇒ bbaabaaaa
3. aababbaa ⇒ baaaabab
4. aaababb ⇒ bbaabaa
5. bbaabaaaaba ⇒ 1
6. ababbaab ⇒ babbaaba
7. ababbaabaa ⇒ bbaabaaaab
8. aababbaaba ⇒ bbaabaaaab
9. bbaabaabaabaaaaba ⇒ aaabab
10. abbaabbbaabaa ⇒ baabaaaabbabb
11. bbaabaaaabbbaabaa ⇒ aababb
12. bbaabaaaabbaaaabab ⇒ ababbaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] baa, [3/1] aba, [3/2] aab, [3/3] bba
Length 4:[4/0] aaba, [4/1] bbaa, [4/2] abaa, [4/3] baab
Length 5:[5/0] bbaab, [5/1] aabaa, [5/2] baaba, [5/3] abbaa
Length 6:[6/0] bbaaba, [6/1] baabaa, [6/2] abbaab, [6/3] aababb

Considering [length 5 / frequency 0] bbaab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bacaaaa ⇒ 1
2. abac ⇒ baca
3. aabac ⇒ bacaa
4. caaaab ⇒ bacaaa
5. cacaa ⇒ bb
6. acaaaac ⇒ baab
7. bbaab ⇒ c
8. baabaaaab ⇒ acaaa
9. aaababb ⇒ caa
10. bacaacaa ⇒ ababb
11. cbaab ⇒ bbaac
12. caabaab ⇒ aaababc
13. bbbacaa ⇒ cac
14. cacbacaa ⇒ bbbac
15. bbababb ⇒ caccaa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] ac, [2/4] ca, [2/5] bb, [2/6] cb
Length 3:[3/0] caa, [3/1] aab, [3/2] aaa, [3/3] bac, [3/4] aca, [3/5] aba, [3/6] baa
Length 4:[4/0] acaa, [4/1] baab, [4/2] baca, [4/3] aaab, [4/4] aaba, [4/5] aaaa, [4/6] babb
Length 5:[5/0] bacaa, [5/1] caaaa, [5/2] ababb, [5/3] aaaab, [5/4] acaaa, [5/5] bbbac, [5/6] cacba

Considering [length 5 / frequency 0] bacaa=d.

Step 3

Rewriting system is complete. See a, b | abbaabaaaab=1⟩.