Morphocompletion for #3259 ⟨a, b | ababbabbbba=1⟩

Solved by morph:6/0,4/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbbaa ⇒ bbaabab
2. bbbbaaba ⇒ ababbabb
3. abbabbbba ⇒ bbbaababb
4. aababbabbbb ⇒ 1
5. ababbabbbababbabbbb ⇒ bbabbbba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] bb, [2/1] ab, [2/2] ba, [2/3] aa
Length 3:[3/0] bbb, [3/1] abb, [3/2] bba, [3/3] bab
Length 4:[4/0] bbbb, [4/1] babb, [4/2] abbb, [4/3] bbba
Length 5:[5/0] abbbb, [5/1] bbbba, [5/2] abbab, [5/3] bbabb
Length 6:[6/0] babbbb, [6/1] abbabb, [6/2] bbabbb, [6/3] bbbbaa

Considering [length 6 / frequency 0] babbbb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caab ⇒ abca
2. aababc ⇒ 1
3. babca ⇒ ababc
4. caacb ⇒ bcaac
5. ccaab ⇒ cabca
6. bcaab ⇒ ababc
7. bbb ⇒ caac
8. caacabcaa ⇒ bb
9. abcabb ⇒ caacaac
10. bbbb ⇒ bcaac
11. babbb ⇒ cabcaa
12. cabcaacaac ⇒ cbb
13. babbcaac ⇒ cb
14. cabbbb ⇒ cabcaac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ca, [2/1] bb, [2/2] ab, [2/3] aa, [2/4] bc, [2/5] ba, [2/6] ac
Length 3:[3/0] caa, [3/1] bbb, [3/2] bca, [3/3] aab, [3/4] bab, [3/5] abc, [3/6] aac
Length 4:[4/0] caac, [4/1] bcaa, [4/2] abca, [4/3] babb, [4/4] cabb, [4/5] babc, [4/6] caab
Length 5:[5/0] cabca, [5/1] bcaac, [5/2] abcaa, [5/3] caaca, [5/4] abbbb, [5/5] cabbb, [5/6] bcabb

Considering [length 4 / frequency 1] bcaa=d.

Step 3

Rewriting system is complete. See a, b | ababbabbbba=1⟩.