Morphocompletion for #3253 ⟨a, b | ababbaabaab=1⟩

Solved by morph:4/2,2/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaaba ⇒ baabaab
2. babbaa ⇒ ababab
3. ababbaa ⇒ aababab
4. abababba ⇒ bbaabaab
5. aabababba ⇒ baabaabab
6. baabaababa ⇒ aabaababab
7. bbaabaaba ⇒ abaababab
8. aabaabababb ⇒ 1
9. baabaababbabbaa ⇒ abab
10. ababababaabababb ⇒ babba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] baa, [3/3] aab
Length 4:[4/0] abab, [4/1] aaba, [4/2] babb, [4/3] baab
Length 5:[5/0] baaba, [5/1] ababa, [5/2] babba, [5/3] ababb
Length 6:[6/0] ababab, [6/1] ababba, [6/2] bababb, [6/3] abaaba

Considering [length 4 / frequency 2] babb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acaab ⇒ aabac
2. acaaacaac ⇒ aacb
3. aabacaac ⇒ abb
4. caabaac ⇒ bb
5. aabaabac ⇒ 1
6. abaabaca ⇒ 1
7. aabacab ⇒ baabaac
8. cabb ⇒ babc
9. caabaab ⇒ baabaca
10. babb ⇒ c
11. cabacaac ⇒ cbb
12. babacaac ⇒ bbb
13. aabababc ⇒ acaac
14. baabaacb ⇒ acaac
15. bbaabaab ⇒ caaba
16. caabaababc ⇒ bc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] ba, [2/3] ac, [2/4] ca, [2/5] bb, [2/6] bc
Length 3:[3/0] aab, [3/1] aba, [3/2] caa, [3/3] aac, [3/4] aca, [3/5] baa, [3/6] bab
Length 4:[4/0] aaba, [4/1] baab, [4/2] caab, [4/3] caac, [4/4] abaa, [4/5] acaa, [4/6] abac
Length 5:[5/0] abaab, [5/1] acaac, [5/2] aabac, [5/3] aabaa, [5/4] baaba, [5/5] caaba, [5/6] abaca

Considering [length 2 / frequency 0] ab=d.

Step 3

Rewriting system is complete. See a, b | ababbaabaab=1⟩.