Morphocompletion for #3252 ⟨a, b | ababbaaabba=1⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbaab ⇒ babbaa
2. abbaaabb ⇒ baababba
3. babbaaabb ⇒ bbaababba
4. bbabbaaaab ⇒ abbababbaa
5. ababbaaab ⇒ bbaaabbaa
6. abbaaabbab ⇒ baabbabbaa
7. bbaababbaaa ⇒ 1
8. babbaaabbaa ⇒ 1
9. bbabbaaaaabb ⇒ abbabaababba
10. abbaaabbbbaaabbaa ⇒ baabab
11. abbaaabbbbaababbaa ⇒ baababb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] aa, [2/2] bb, [2/3] ba
Length 3:[3/0] abb, [3/1] bba, [3/2] baa, [3/3] aab, [3/4] aaa, [3/5] bab, [3/6] aba
Length 4:[4/0] bbaa, [4/1] abba, [4/2] aaab, [4/3] baaa, [4/4] aabb, [4/5] babb, [4/6] bbab
Length 5:[5/0] abbaa, [5/1] bbaaa, [5/2] aaabb, [5/3] baaab, [5/4] babba, [5/5] bbaab, [5/6] ababb
Length 6:[6/0] abbaaa, [6/1] babbaa, [6/2] baaabb, [6/3] bbaaab, [6/4] aabbaa, [6/5] ababba, [6/6] bbabba
Length 7:[7/0] abbaaab, [7/1] babbaaa, [7/2] bbaaabb, [7/3] ababbaa, [7/4] aaabbaa, [7/5] bbabbaa, [7/6] baaabba

Considering [length 5 / frequency 0] abbaa=c.

Step 2

Rewriting system is complete. See a, b | ababbaaabba=1⟩.