Morphocompletion for #3223 ⟨a, b | abaabbbabba=1⟩

Solved by morph:3/2,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. bbabbaa ⇒ aabbbab
2. baabaabbb ⇒ aabbbabba
3. baabbbabba ⇒ abaabbbabb
4. babbaaba ⇒ aabaabbb
5. bbaabaabb ⇒ abaabbbab
6. aabaabbbabb ⇒ 1
7. bbababaabbbabb ⇒ aabbbabbbbabba
8. baabbbaaabbbab ⇒ abaabbbabbbbaa
9. babbaaaabaabbb ⇒ aabaabbbbbaaba
10. aabaabbbabaabbbab ⇒ babbaa
11. abaabbbabbbbaabaabb ⇒ baabbbab
12. aabaabbbababaabbbab ⇒ baabaabb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] bb, [2/1] ba, [2/2] ab, [2/3] aa
Length 3:[3/0] aab, [3/1] abb, [3/2] baa, [3/3] bba
Length 4:[4/0] baab, [4/1] aabb, [4/2] bbab, [4/3] abbb
Length 5:[5/0] baabb, [5/1] aabbb, [5/2] abaab, [5/3] bbbab
Length 6:[6/0] baabbb, [6/1] abaabb, [6/2] abbbab, [6/3] aabaab

Considering [length 3 / frequency 2] baa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cbccbbbbccbbb ⇒ b
2. cbccbbbbccbc ⇒ ccbbcbccbbbc
3. abccbbb ⇒ 1
4. abccbbcbccbbb ⇒ a
5. ba ⇒ cbccbbb
6. babcc ⇒ abccb
7. bbabcc ⇒ babccb
8. bbabccb ⇒ 1
9. bbbabcc ⇒ 1
10. cbbbab ⇒ bbbabc
11. bccbbbac ⇒ c
12. aa ⇒ babccbc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] bb, [2/1] cb, [2/2] bc, [2/3] cc, [2/4] ab, [2/5] ba, [2/6] ac
Length 3:[3/0] bcc, [3/1] bbb, [3/2] ccb, [3/3] cbb, [3/4] abc, [3/5] bba, [3/6] bab
Length 4:[4/0] abcc, [4/1] bccb, [4/2] cbbb, [4/3] bbab, [4/4] ccbb, [4/5] babc, [4/6] cbcc
Length 5:[5/0] ccbbb, [5/1] bccbb, [5/2] abccb, [5/3] bbabc, [5/4] babcc, [5/5] cbccb, [5/6] bbbab

Considering [length 4 / frequency 0] abcc=d.

Step 3

Rewriting system is complete. See a, b | abaabbbabba=1⟩.