Morphocompletion for #3221 ⟨a, b | abaabbbaaba=1⟩

Solved by morph:3/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbbaab ⇒ abaabbb
2. abbbabbaab ⇒ abbbaaabbb
3. abaabbbbbaab ⇒ abaabaabbbbb
4. baabaabbba ⇒ abaabaabbb
5. aaabaabaabbbbbbbb ⇒ abbbbb
6. abaabaabbbbbbbaab ⇒ abbbbb
7. abbbaaabaabaabbb ⇒ abbba
8. abbbaaaabaabaabbb ⇒ abbbaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] bb, [2/2] aa, [2/3] ba
Length 3:[3/0] bbb, [3/1] aab, [3/2] baa, [3/3] abb
Length 4:[4/0] baab, [4/1] abbb, [4/2] abaa, [4/3] bbbb
Length 5:[5/0] abaab, [5/1] abbba, [5/2] bbbbb, [5/3] aabaa
Length 6:[6/0] aabaab, [6/1] baabbb, [6/2] abaabb, [6/3] baabaa

Considering [length 3 / frequency 0] bbb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cb ⇒ bc
2. bbb ⇒ c
3. caa ⇒ baabb
4. bbaa ⇒ aabb
5. acaab ⇒ abaac
6. acaac ⇒ abaabbc
7. baabaaca ⇒ abaabaac
8. bbabaabaac ⇒ caabaaca
9. aabaabaac ⇒ 1
10. aabaabaabc ⇒ b
11. aabaabaabbc ⇒ bb
12. baabaabaabb ⇒ 1
13. caabaacaa ⇒ bb
14. abaabaabbcaa ⇒ abb
15. aabaabaaaabc ⇒ baa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] ac, [2/4] bb, [2/5] ca, [2/6] bc
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] caa, [3/4] aac, [3/5] aca, [3/6] bba
Length 4:[4/0] aaba, [4/1] abaa, [4/2] baab, [4/3] acaa, [4/4] baac, [4/5] caab, [4/6] aabc
Length 5:[5/0] aabaa, [5/1] abaab, [5/2] baaba, [5/3] abaac, [5/4] baabb, [5/5] baaca, [5/6] aabbc

Considering [length 3 / frequency 0] aab=d.

Step 3

Rewriting system is complete. See a, b | abaabbbaaba=1⟩.