Morphocompletion for #3215 ⟨a, b | abaabbaabab=1⟩

Solved by morph:4/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baabba ⇒ abbaab
2. abaabba ⇒ aabbaab
3. baababa ⇒ ababaab
4. baababbaab ⇒ abbaababba
5. aabababaabb ⇒ 1
6. ababaababbaab ⇒ ba
7. aababaababbbaab ⇒ baba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] ab, [2/2] aa, [2/3] bb
Length 3:[3/0] aab, [3/1] aba, [3/2] baa, [3/3] bab
Length 4:[4/0] baab, [4/1] abab, [4/2] aaba, [4/3] baba
Length 5:[5/0] aabab, [5/1] ababa, [5/2] baaba, [5/3] bbaab
Length 6:[6/0] aababa, [6/1] baabab, [6/2] ababaa, [6/3] abbaab

Considering [length 4 / frequency 0] baab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cab ⇒ acccc
2. ccac ⇒ ab
3. ccccac ⇒ cacccc
4. ba ⇒ cacc
5. acacccc ⇒ 1
6. accac ⇒ aab
7. cacac ⇒ acacc
8. ccaab ⇒ abcac
9. aabcccac ⇒ acc
10. acaabccc ⇒ cac
11. caacacb ⇒ ac
12. aacaabcc ⇒ aca
13. aacaabb ⇒ caac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ac, [2/1] cc, [2/2] ca, [2/3] aa, [2/4] ab, [2/5] bc, [2/6] bb
Length 3:[3/0] cac, [3/1] ccc, [3/2] aca, [3/3] aab, [3/4] cca, [3/5] caa, [3/6] aac
Length 4:[4/0] ccac, [4/1] aaca, [4/2] caab, [4/3] acac, [4/4] acaa, [4/5] aabc, [4/6] abcc
Length 5:[5/0] aabcc, [5/1] aacaa, [5/2] acaab, [5/3] cccac, [5/4] abccc, [5/5] caaca, [5/6] caabb

Considering [length 3 / frequency 0] cac=d.

Step 3

Rewriting system is complete. See a, b | abaabbaabab=1⟩.