Morphocompletion for #3211 ⟨a, b | abaababbaab=1⟩

Back:⟨a, b | abaababbaab=1⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabab ⇒ baaba
2. ababbaab ⇒ bbbaabaa
3. bababbaab ⇒ bbbbaabaa
4. bbaabaaab ⇒ abbbaabaa
5. babbbaabaaa ⇒ 1
6. ababbbaabaa ⇒ 1
7. ababbbaabbaaba ⇒ bab
8. ababbbaabbbaaba ⇒ babb
9. baabaabbbaabaa ⇒ aab
10. babbbaabaabaaba ⇒ abab
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] bab, [3/4] bba, [3/5] abb, [3/6] bbb
Length 4:[4/0] baab, [4/1] aaba, [4/2] bbaa, [4/3] abab, [4/4] abaa, [4/5] babb, [4/6] abbb
Length 5:[5/0] baaba, [5/1] bbaab, [5/2] aabaa, [5/3] ababb, [5/4] abbba, [5/5] bbbaa, [5/6] babbb
Length 6:[6/0] baabaa, [6/1] bbaaba, [6/2] abbbaa, [6/3] bbbaab, [6/4] babbba, [6/5] ababbb, [6/6] abbaab
Length 7:[7/0] bbaabaa, [7/1] abbbaab, [7/2] babbbaa, [7/3] ababbba, [7/4] bbbaaba, [7/5] baabaab, [7/6] babbaab

Considering [length 5 / frequency 0] baaba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaababbaab=1⟩.