Morphocompletion for #3190 ⟨a, b | abaaabababa=1⟩

Solved by morph:2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baabaa ⇒ abaaab
2. baabaaab ⇒ abaaabab
3. aabababa ⇒ abaaabab
4. babaaba ⇒ aababab
5. baabaaaaba ⇒ abaaabaaba
6. abaaabbaa ⇒ baaabaaab
7. aabaaababab ⇒ 1
8. babababa ⇒ bbaaabab
9. baabaaaaababab ⇒ aba
10. aabbaaaaabababb ⇒ baba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] aa, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] bab
Length 4:[4/0] aaba, [4/1] baba, [4/2] abab, [4/3] baab
Length 5:[5/0] baaba, [5/1] babab, [5/2] ababa, [5/3] aabaa
Length 6:[6/0] ababab, [6/1] bababa, [6/2] baabaa, [6/3] aababa

Considering [length 2 / frequency 0] ba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acccac ⇒ cccaca
2. caacc ⇒ accca
3. aaccc ⇒ ccaca
4. cccacaa ⇒ 1
5. acaac ⇒ cacaa
6. ccacaac ⇒ 1
7. cacaaca ⇒ aacccaa
8. ccacaaacc ⇒ aaccaccca
9. ccacacacaa ⇒ aac
10. ccacaccacaa ⇒ aacc
11. cacaaaac ⇒ acacacaa
12. b ⇒ ccccaca
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] ac, [2/1] ca, [2/2] cc, [2/3] aa
Length 3:[3/0] cac, [3/1] aca, [3/2] caa, [3/3] aac, [3/4] cca, [3/5] acc, [3/6] ccc
Length 4:[4/0] acaa, [4/1] caca, [4/2] ccac, [4/3] caac, [4/4] aacc, [4/5] accc, [4/6] aaac
Length 5:[5/0] cacaa, [5/1] ccaca, [5/2] cccac, [5/3] acaac, [5/4] cacac, [5/5] aaaac, [5/6] acaaa

Considering [length 4 / frequency 0] acaa=d.

Step 3

Rewriting system is complete. See a, b | abaaabababa=1⟩.