Morphocompletion for #3188 ⟨a, b | abaaabaabba=1⟩

Solved by morph:4/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabb ⇒ bbaaba
2. abaabba ⇒ bbaabaa
3. aaabaab ⇒ baabaaa
4. baabaaab ⇒ aabbaaba
5. bbaabaaab ⇒ baabbaaba
6. baabbaabaaa ⇒ 1
7. baabaaaaaab ⇒ aaaaabbaaba
8. baabaaaaabb ⇒ aaababbaaba
9. baabaaaaaaaaab ⇒ aaaaaaaabbaaba
10. baabaaaaabaaab ⇒ aaabaaaabbaaba
11. baabaaaaaaaabb ⇒ aaaaaababbaaba
12. baabbaababaabaaa ⇒ abaab
13. baabbaabaabaabaaa ⇒ aabaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aab, [3/2] aaa, [3/3] aba
Length 4:[4/0] baab, [4/1] abaa, [4/2] aaaa, [4/3] aaab
Length 5:[5/0] baaba, [5/1] aabaa, [5/2] abaaa, [5/3] aaaaa
Length 6:[6/0] baabaa, [6/1] aabaaa, [6/2] baabba, [6/3] aaaaaa

Considering [length 4 / frequency 0] baab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acc ⇒ cca
2. ccaaa ⇒ 1
3. aaac ⇒ caaa
4. caaac ⇒ 1
5. caab ⇒ baac
6. ccacaaa ⇒ ac
7. baab ⇒ c
8. abaaacc ⇒ ab
9. bcaaab ⇒ cca
10. ccaaabaa ⇒ baa
11. caaabaac ⇒ aab
12. bcaaabaa ⇒ 1
13. bcaaabcaaa ⇒ ac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ca, [2/2] ab, [2/3] ac, [2/4] cc, [2/5] bc, [2/6] ba
Length 3:[3/0] aaa, [3/1] caa, [3/2] aab, [3/3] baa, [3/4] bca, [3/5] aac, [3/6] cca
Length 4:[4/0] caaa, [4/1] abaa, [4/2] bcaa, [4/3] aaab, [4/4] ccaa, [4/5] aaba, [4/6] aaac
Length 5:[5/0] bcaaa, [5/1] caaab, [5/2] aabaa, [5/3] aaaba, [5/4] abaaa, [5/5] abaac, [5/6] acaaa

Considering [length 3 / frequency 0] aaa=d.

Step 3

Rewriting system is complete. See a, b | abaaabaabba=1⟩.