Morphocompletion for #3187 ⟨a, b | abaaabaabab=1⟩

Solved by morph:2/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaaaba ⇒ aaabaab
2. babaaab ⇒ abababa
3. bababaa ⇒ abaabab
4. baaabaab ⇒ aabaabab
5. aaabaababab ⇒ 1
6. aabaabababa ⇒ 1
7. abaaaaabaab ⇒ aaabaabaaba
8. aabaabaabaabab ⇒ baa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa
Length 3:[3/0] aba, [3/1] aab, [3/2] baa, [3/3] bab
Length 4:[4/0] abaa, [4/1] aaba, [4/2] baba, [4/3] baab
Length 5:[5/0] abaab, [5/1] aabaa, [5/2] aaaba, [5/3] babab
Length 6:[6/0] aabaab, [6/1] abaaba, [6/2] bababa, [6/3] baabab

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acacccc ⇒ b
2. cacccac ⇒ b
3. ccaacc ⇒ acccac
4. ab ⇒ c
5. bacccc ⇒ cacccb
6. bccac ⇒ caccb
7. aacaccc ⇒ 1
8. caaca ⇒ aacac
9. acaccb ⇒ cccac
10. ccaacb ⇒ acccc
11. baacc ⇒ acacb
12. bcaacc ⇒ cccac
13. aacacb ⇒ caacc
14. baaca ⇒ acac
15. bcaacb ⇒ cccc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] ac, [2/2] ca, [2/3] aa, [2/4] cb, [2/5] ba, [2/6] bc
Length 3:[3/0] aac, [3/1] acc, [3/2] aca, [3/3] cac, [3/4] ccc, [3/5] acb, [3/6] caa
Length 4:[4/0] aaca, [4/1] caac, [4/2] acac, [4/3] aacc, [4/4] cacc, [4/5] accc, [4/6] bcaa
Length 5:[5/0] acacc, [5/1] caccc, [5/2] bcaac, [5/3] caacb, [5/4] aacac, [5/5] ccaac, [5/6] caacc

Considering [length 4 / frequency 0] aaca=d.

Step 3

Rewriting system is complete. See a, b | abaaabaabab=1⟩.