Morphocompletion for #3181 ⟨a, b | abaaaabbaab=1⟩

Solved by morph:6/1,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. babaaaab ⇒ aabbaaba
2. aaabbaab ⇒ baaaabba
3. aabbaabab ⇒ bbaababaa
4. ababaaaab ⇒ baaaabbaa
5. aaaabbaab ⇒ abaaaabba
6. bbaababaaaa ⇒ 1
7. aabbaababaa ⇒ 1
8. ababaaaabba ⇒ 1
9. abbabaaaabbaa ⇒ ab
10. abbbabaaaabbaa ⇒ abb
11. bbaababaaaaab ⇒ ab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] aaa, [3/2] baa, [3/3] aba
Length 4:[4/0] aaab, [4/1] bbaa, [4/2] aaaa, [4/3] abba
Length 5:[5/0] aaaab, [5/1] aabba, [5/2] babaa, [5/3] bbaab
Length 6:[6/0] aabbaa, [6/1] abaaaa, [6/2] ababaa, [6/3] babaaa

Considering [length 6 / frequency 1] abaaaa=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. caa ⇒ cbcbbcbbac
2. cbcbbaa ⇒ c
3. cbcbbcbbacbcbba ⇒ ca
4. cbbaab ⇒ 1
5. acbbac ⇒ cbbaca
6. cbcbbcbbacbcbbcbbac ⇒ ccbbac
7. aaa ⇒ cbbacbcbba
8. cacabcbba ⇒ cac
9. cbbacabcbba ⇒ cbbac
10. caccabcbba ⇒ cacc
11. cbbaccabcbba ⇒ cbbacc
12. cacccabcbba ⇒ caccc
13. caccccabcbba ⇒ cacccc
14. abcbbacbcbba ⇒ cbcbba
15. cbbacabbaab ⇒ acbba
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cb, [2/1] ba, [2/2] bb, [2/3] ca, [2/4] ac, [2/5] bc, [2/6] ab
Length 3:[3/0] bba, [3/1] cbb, [3/2] bcb, [3/3] bac, [3/4] cbc, [3/5] abc, [3/6] cac
Length 4:[4/0] cbba, [4/1] bcbb, [4/2] bbac, [4/3] cbcb, [4/4] abcb, [4/5] cacc, [4/6] cabc
Length 5:[5/0] bcbba, [5/1] cbbac, [5/2] cbcbb, [5/3] abcbb, [5/4] cabcb, [5/5] bbaab, [5/6] cbbaa

Considering [length 4 / frequency 0] cbba=d.

Step 3

Rewriting system is complete. See a, b | abaaaabbaab=1⟩.