Morphocompletion for #3180 ⟨a, b | abaaaababba=1⟩

Solved by morph:6/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aaaababba ⇒ baabaaaab
2. baabaaaaba ⇒ aabaaaabab
3. aababbaa ⇒ baaaabab
4. bbaabaa ⇒ aaababb
5. aabbaabaa ⇒ aaaaababb
6. aabaaaababb ⇒ 1
7. bbaabaaaab ⇒ abaaaababb
8. aabaaaababaaababb ⇒ baabaa
9. baaaabababaaaababb ⇒ aababba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] aaa
Length 4:[4/0] aaba, [4/1] abaa, [4/2] aaab, [4/3] babb
Length 5:[5/0] aabaa, [5/1] aaaab, [5/2] ababb, [5/3] aabab
Length 6:[6/0] aababb, [6/1] baaaab, [6/2] aaaaba, [6/3] baabaa

Considering [length 6 / frequency 0] aababb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aacaab ⇒ 1
2. caaba ⇒ acaab
3. acaaba ⇒ 1
4. baac ⇒ caab
5. abaac ⇒ acaab
6. aabaac ⇒ 1
7. baaca ⇒ abaac
8. acc ⇒ bb
9. caacaa ⇒ aabab
10. aababb ⇒ c
11. acaabab ⇒ b
12. baaacaab ⇒ ba
13. caabc ⇒ babb
14. acaabbb ⇒ cc
15. abaacbb ⇒ cc
16. ababbc ⇒ baacbb
17. aabababaac ⇒ caaca
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ac, [2/3] ba, [2/4] ca, [2/5] bb, [2/6] bc
Length 3:[3/0] aba, [3/1] aab, [3/2] aac, [3/3] caa, [3/4] aca, [3/5] baa, [3/6] bab
Length 4:[4/0] caab, [4/1] aaba, [4/2] acaa, [4/3] baac, [4/4] abab, [4/5] aaca, [4/6] abaa
Length 5:[5/0] acaab, [5/1] abaac, [5/2] aabab, [5/3] aacaa, [5/4] ababb, [5/5] caaba, [5/6] babbc

Considering [length 4 / frequency 0] caab=d.

Step 3

Rewriting system is complete. See a, b | abaaaababba=1⟩.