Morphocompletion for #3173 ⟨a, b | abaaaaabaab=1⟩

Back:⟨a, b | abaaaaabaab=1⟩

Solved by morph:3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baaaaaba ⇒ aaaabaab
2. ababaaa ⇒ baaaaab
3. babaaaa ⇒ aaabaab
4. aaaaabaabab ⇒ 1
5. baababa ⇒ abaabab
6. aaabaabaabaabab ⇒ baba
7. aaabaabaaabaabab ⇒ babaa
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab
Length 3:[3/0] aba, [3/1] aaa, [3/2] baa, [3/3] aab, [3/4] bab
Length 4:[4/0] aaba, [4/1] abab, [4/2] abaa, [4/3] baab, [4/4] aaab, [4/5] aaaa, [4/6] baaa
Length 5:[5/0] baaba, [5/1] aaaba, [5/2] aabab, [5/3] aabaa, [5/4] abaab, [5/5] ababa, [5/6] baaaa
Length 6:[6/0] baabab, [6/1] abaaba, [6/2] aabaab, [6/3] aaabaa, [6/4] babaaa, [6/5] baabaa, [6/6] aaaaba
Length 7:[7/0] abaabab, [7/1] aabaaba, [7/2] aaabaab, [7/3] aaaaaba, [7/4] abaabaa, [7/5] baabaab, [7/6] baaaaab

Considering [length 3 / frequency 0] aba=c.

Step 2

Rewriting system is complete. See ⟨a, b | abaaaaabaab=1⟩.