Morphocompletion for #3153 ⟨a, b | aabbbbaaaba=1⟩

Solved by morph:3/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bbbaaa ⇒ aaabbb
2. bbbaaab ⇒ aaabbbb
3. bbbbaaaba ⇒ abbbbaaab
4. aaabaaabbbbbbb ⇒ bbb
5. aaabbbbaaab ⇒ 1
6. baaabaaabbbbb ⇒ bb
7. bbaaabaaabbb ⇒ aaabaaabbbbb
8. bbbaaaaaabbbb ⇒ aaaaaabbbbbbb
9. aaabaaaaaabbbbbbbbbb ⇒ bbaaabbbb
10. baaabaaabbaaabbb ⇒ bbaaa
11. aaaaaabaaaaaabbbbbbbbbb ⇒ aaabbaaabbbb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] bb, [2/1] aa, [2/2] ab, [2/3] ba
Length 3:[3/0] bbb, [3/1] aaa, [3/2] aab, [3/3] baa
Length 4:[4/0] bbbb, [4/1] aaab, [4/2] baaa, [4/3] aaaa
Length 5:[5/0] bbbbb, [5/1] baaab, [5/2] aaaba, [5/3] aaabb
Length 6:[6/0] bbbbbb, [6/1] aaabbb, [6/2] aaabaa, [6/3] bbaaab

Considering [length 3 / frequency 0] bbb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bc ⇒ cb
2. bbb ⇒ c
3. caaac ⇒ aaacc
4. caaab ⇒ aaacb
5. cbaaac ⇒ baaacc
6. cbaaab ⇒ baaacb
7. cbbaaac ⇒ bbaaacc
8. cbbaaab ⇒ bbaaacb
9. baaacba ⇒ abaaacb
10. cbaaaba ⇒ acbaaab
11. bbacbaaac ⇒ ccaaababb
12. bbacbaaab ⇒ ccaaaba
13. cbbaaaba ⇒ bacbaaab
14. bbaacbaaab ⇒ ccaaabaa
15. aaabaaaccb ⇒ c
16. aaacbaaac ⇒ bb
17. aaacbaaab ⇒ 1
18. ccaaabaaa ⇒ bb
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] cb, [2/3] ac, [2/4] ab, [2/5] bb, [2/6] ca
Length 3:[3/0] aaa, [3/1] baa, [3/2] aab, [3/3] aac, [3/4] cba, [3/5] bba, [3/6] aba
Length 4:[4/0] aaab, [4/1] baaa, [4/2] aaac, [4/3] cbaa, [4/4] acba, [4/5] aaba, [4/6] cbba
Length 5:[5/0] baaab, [5/1] cbaaa, [5/2] baaac, [5/3] aaaba, [5/4] cbbaa, [5/5] acbaa, [5/6] aacba

Considering [length 4 / frequency 0] aaab=d.

Step 3

Rewriting system is complete. See a, b | aabbbbaaaba=1⟩.