Morphocompletion for #3139 ⟨a, b | aabbbaabaab=1⟩

Solved by morph:2/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. bbaab ⇒ aabbb
2. bbaabaab ⇒ aabbbaab
3. bbaaaabbb ⇒ aaaabbbbb
4. aabbbaabaab ⇒ 1
5. bbaaaabaabbb ⇒ aaaabaabbbbb
6. bbaaaaaabbbbb ⇒ aaaaaabbbbbbb
7. bbaaaabaabaabbb ⇒ aaaabaabaabbbbb
8. bbaaaaaabaabbbbb ⇒ aaaaaabaabbbbbbb
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] bb, [2/1] aa, [2/2] ab, [2/3] ba
Length 3:[3/0] aab, [3/1] bba, [3/2] bbb, [3/3] aaa
Length 4:[4/0] bbaa, [4/1] baab, [4/2] aaaa, [4/3] abbb
Length 5:[5/0] bbaaa, [5/1] aabbb, [5/2] abaab, [5/3] aabaa
Length 6:[6/0] bbaaaa, [6/1] aabaab, [6/2] baabbb, [6/3] abbbbb

Considering [length 2 / frequency 0] bb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bc ⇒ cb
2. bb ⇒ c
3. aac ⇒ caa
4. ccaabaabaa ⇒ b
5. caabaabaab ⇒ 1
6. baabaabaa ⇒ aabaabaab
7. ccaabaabacaa ⇒ bac
8. ccaabaabaccaa ⇒ bacc
9. caccacbaabaaba ⇒ cacc
10. ccaaaabaabaa ⇒ aab
11. ccbaabaabacaa ⇒ cac
12. caaaabaabaab ⇒ aa
13. ccbaaaabaabaa ⇒ baab
14. cbaaaabaabaab ⇒ baa
15. caaaaaabaabaab ⇒ aaaa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] ca, [2/4] cc, [2/5] ac, [2/6] cb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] caa, [3/4] aaa, [3/5] cca, [3/6] cba
Length 4:[4/0] aaba, [4/1] abaa, [4/2] baab, [4/3] ccaa, [4/4] aaaa, [4/5] aaab, [4/6] caaa
Length 5:[5/0] aabaa, [5/1] abaab, [5/2] baaba, [5/3] ccaab, [5/4] aaaba, [5/5] aaaab, [5/6] caaaa

Considering [length 3 / frequency 0] aab=d.

Step 3

Rewriting system is complete. See a, b | aabbbaabaab=1⟩.