Morphocompletion for #3125 ⟨a, b | aabbabbaaab=1⟩

Solved by morph:6/1,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: arenaTotalLimit

#Rule
1. babbaaab ⇒ aabbabba
2. aabbabbaaab ⇒ 1
3. babbaaaaabbabba ⇒ aabbabbaabbaaab
4. babbaaaaabaabbabb ⇒ babbaa
5. aabbabbaabbaaabaab ⇒ babbaaa
6. babbaaaaabaabbabba ⇒ babbaaa
7. babbaaaaaaabaabbabb ⇒ babbaaaa
8. babbaaaaabaabaabbabba ⇒ babbaaaaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ba, [2/1] aa, [2/2] ab, [2/3] bb
Length 3:[3/0] abb, [3/1] aab, [3/2] bba, [3/3] aaa
Length 4:[4/0] abba, [4/1] babb, [4/2] aaaa, [4/3] aaab
Length 5:[5/0] babba, [5/1] aabba, [5/2] abbaa, [5/3] bbabb
Length 6:[6/0] babbaa, [6/1] aabbab, [6/2] abbabb, [6/3] abbaaa

Considering [length 6 / frequency 1] aabbab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. bbab ⇒ abcbc
2. cbac ⇒ bab
3. bcba ⇒ abcb
4. cbabab ⇒ babbac
5. ccbaa ⇒ aabb
6. aaabcb ⇒ 1
7. baaabc ⇒ 1
8. caaabc ⇒ aabba
9. bbaaab ⇒ aabccba
10. cbaaa ⇒ aaabc
11. cbaaab ⇒ 1
12. aaabcabcb ⇒ cba
13. abcbcaaabc ⇒ bba
14. baaabccba ⇒ cba
15. aaabcaabcb ⇒ cbaa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ab, [2/2] cb, [2/3] ba, [2/4] bc, [2/5] ca, [2/6] bb
Length 3:[3/0] aaa, [3/1] abc, [3/2] cba, [3/3] aab, [3/4] baa, [3/5] bcb, [3/6] bab
Length 4:[4/0] aaab, [4/1] aabc, [4/2] baaa, [4/3] abcb, [4/4] cbaa, [4/5] ccba, [4/6] caaa
Length 5:[5/0] aaabc, [5/1] baaab, [5/2] aabcb, [5/3] caaab, [5/4] cbaaa, [5/5] bbaaa, [5/6] aabca

Considering [length 5 / frequency 0] aaabc=d.

Step 3

Rewriting system is complete. See a, b | aabbabbaaab=1⟩.