Morphocompletion for #3120 ⟨a, b | aabbababaab=1⟩

Solved by morph:2/0,5/2. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabba ⇒ baabaab
2. aabbab ⇒ bababa
3. aabbaba ⇒ bababaa
4. aabaabba ⇒ abaabaab
5. abbababa ⇒ baabaabb
6. ababaabaab ⇒ bababaabaa
7. abaabaabb ⇒ bababaaba
8. bbababaabaa ⇒ 1
9. ababbababaaba ⇒ ab
10. babababababaabaa ⇒ aabba
11. bbababaababababa ⇒ abbab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aba, [3/1] bab, [3/2] aab, [3/3] baa
Length 4:[4/0] baba, [4/1] abaa, [4/2] abab, [4/3] baab
Length 5:[5/0] ababa, [5/1] abaab, [5/2] babab, [5/3] bbaba
Length 6:[6/0] bababa, [6/1] abaaba, [6/2] bbabab, [6/3] ababaa

Considering [length 2 / frequency 0] ab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cccacaa ⇒ accacac
2. cccacac ⇒ a
3. bccacaa ⇒ ccacac
4. bccacac ⇒ 1
5. ab ⇒ c
6. cbccaa ⇒ bcacac
7. cbccaca ⇒ 1
8. cbccacc ⇒ b
9. acb ⇒ bcccccaca
10. bbccaca ⇒ cbccac
11. bbccacccca ⇒ cbc
12. bbccacccccccaca ⇒ cb
13. cbb ⇒ bbccacccccccacc
14. cbcb ⇒ bbccaccccc
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] ca, [2/2] ac, [2/3] cb, [2/4] bc, [2/5] bb, [2/6] aa
Length 3:[3/0] cac, [3/1] cca, [3/2] ccc, [3/3] bcc, [3/4] aca, [3/5] cbc, [3/6] bbc
Length 4:[4/0] bcca, [4/1] ccac, [4/2] caca, [4/3] ccca, [4/4] bbcc, [4/5] cbcc, [4/6] cccc
Length 5:[5/0] ccaca, [5/1] bccac, [5/2] bbcca, [5/3] cbcca, [5/4] cccac, [5/5] ccacc, [5/6] cacac

Considering [length 5 / frequency 2] bbcca=d.

Step 3

Rewriting system is complete. See a, b | aabbababaab=1⟩.