Morphocompletion for #3119 ⟨a, b | aabbabaabba=1⟩

Back:⟨a, b | aabbabaabba=1⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. aabbab ⇒ baabba
2. abbabaab ⇒ bbaaabba
3. abbabaabba ⇒ bbabaabbaa
4. baabbaaab ⇒ abbaaabba
5. bbabaabbaab ⇒ abbabbaabba
6. aabbaaabb ⇒ babaabbaa
7. bbabaabbaaa ⇒ 1
8. bbaabbaabaab ⇒ aabbbbaaabba
9. abbabaaaabb ⇒ bbaabaabbaa
10. abbabaabbbaabba ⇒ bbab
11. abbabaabbbbaabba ⇒ bbabb
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] abb, [3/1] bba, [3/2] aab, [3/3] baa, [3/4] bab, [3/5] aba, [3/6] aaa
Length 4:[4/0] abba, [4/1] aabb, [4/2] baab, [4/3] bbab, [4/4] bbaa, [4/5] abaa, [4/6] baba
Length 5:[5/0] aabba, [5/1] abbab, [5/2] baabb, [5/3] abaab, [5/4] bbaba, [5/5] babaa, [5/6] bbaab
Length 6:[6/0] baabba, [6/1] abbaba, [6/2] bbabaa, [6/3] babaab, [6/4] aabbaa, [6/5] abaabb, [6/6] abbaaa
Length 7:[7/0] abbabaa, [7/1] bbabaab, [7/2] bbaabba, [7/3] aabbaaa, [7/4] baabbaa, [7/5] babaabb, [7/6] abaabba

Considering [length 5 / frequency 0] aabba=c.

Step 2

Rewriting system is complete. See ⟨a, b | aabbabaabba=1⟩.