Morphocompletion for #3115 ⟨a, b | aabbabaaaab=1⟩

Solved by morph:5/0,5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abbabaaaa ⇒ baaaabaab
2. abaaaabaab ⇒ babaaaabaa
3. aabbabaa ⇒ babaaaab
4. aabaabb ⇒ bbabaaa
5. bbabaaaabaa ⇒ 1
6. abaabbab ⇒ baabbaba
7. bbabaaababaaaabaa ⇒ aabaab
8. aabbbbabaaaab ⇒ babaaaabbbaba
9. aabbbaabbaba ⇒ babaaaabbbab
10. aabbabbbabaaa ⇒ babaaaabbaabb
11. bbabaaaabbaaaabaab ⇒ abaabba
12. bbabaaaababbabaaa ⇒ abaabb
13. bbabaaaabababaaaab ⇒ abbabaa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb
Length 3:[3/0] aab, [3/1] aba, [3/2] aaa, [3/3] baa
Length 4:[4/0] abaa, [4/1] bbab, [4/2] baba, [4/3] baaa
Length 5:[5/0] bbaba, [5/1] abaaa, [5/2] babaa, [5/3] aaaab
Length 6:[6/0] bbabaa, [6/1] babaaa, [6/2] baaaab, [6/3] abaaaa

Considering [length 5 / frequency 0] bbaba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. baacaaa ⇒ 1
2. abaac ⇒ baaca
3. aabaac ⇒ abaaca
4. aabaaca ⇒ 1
5. caaab ⇒ baaca
6. cacaa ⇒ bb
7. cacaaa ⇒ bba
8. aacaaac ⇒ baba
9. bbaba ⇒ c
10. babaaaab ⇒ aaca
11. aabaabb ⇒ caa
12. cbaaaab ⇒ bbaaaca
13. aacababa ⇒ babaaaac
14. cbaacaa ⇒ bbab
15. cabaaca ⇒ bbab
16. cacaaac ⇒ bbac
17. bbbaaca ⇒ cac
18. cacababa ⇒ bbacaaac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ca, [2/2] ba, [2/3] ac, [2/4] ab, [2/5] bb, [2/6] cb
Length 3:[3/0] aac, [3/1] aba, [3/2] aca, [3/3] aab, [3/4] baa, [3/5] aaa, [3/6] caa
Length 4:[4/0] aaca, [4/1] baac, [4/2] caca, [4/3] baba, [4/4] acaa, [4/5] caaa, [4/6] abaa
Length 5:[5/0] baaca, [5/1] acaaa, [5/2] aabaa, [5/3] aacaa, [5/4] caaac, [5/5] cacaa, [5/6] abaac

Considering [length 5 / frequency 0] baaca=d.

Step 3

Rewriting system is complete. See a, b | aabbabaaaab=1⟩.