| Back: | ⟨a, b | aabbabaaaab=1⟩ |
|---|
Solved by morph:5/0,5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | abbabaaaa ⇒ baaaabaab |
| 2. | abaaaabaab ⇒ babaaaabaa |
| 3. | aabbabaa ⇒ babaaaab |
| 4. | aabaabb ⇒ bbabaaa |
| 5. | bbabaaaabaa ⇒ 1 |
| 6. | abaabbab ⇒ baabbaba |
| 7. | bbabaaababaaaabaa ⇒ aabaab |
| 8. | aabbbbabaaaab ⇒ babaaaabbbaba |
| 9. | aabbbaabbaba ⇒ babaaaabbbab |
| 10. | aabbabbbabaaa ⇒ babaaaabbaabb |
| 11. | bbabaaaabbaaaabaab ⇒ abaabba |
| 12. | bbabaaaababbabaaa ⇒ abaabb |
| 13. | bbabaaaabababaaaab ⇒ abbabaa |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] aa, [2/1] ab, [2/2] ba, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] aba, [3/2] aaa, [3/3] baa |
| Length 4: | [4/0] abaa, [4/1] bbab, [4/2] baba, [4/3] baaa |
| Length 5: | [5/0] bbaba, [5/1] abaaa, [5/2] babaa, [5/3] aaaab |
| Length 6: | [6/0] bbabaa, [6/1] babaaa, [6/2] baaaab, [6/3] abaaaa |
Considering [length 5 / frequency 0] bbaba=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | baacaaa ⇒ 1 |
| 2. | abaac ⇒ baaca |
| 3. | aabaac ⇒ abaaca |
| 4. | aabaaca ⇒ 1 |
| 5. | caaab ⇒ baaca |
| 6. | cacaa ⇒ bb |
| 7. | cacaaa ⇒ bba |
| 8. | aacaaac ⇒ baba |
| 9. | bbaba ⇒ c |
| 10. | babaaaab ⇒ aaca |
| 11. | aabaabb ⇒ caa |
| 12. | cbaaaab ⇒ bbaaaca |
| 13. | aacababa ⇒ babaaaac |
| 14. | cbaacaa ⇒ bbab |
| 15. | cabaaca ⇒ bbab |
| 16. | cacaaac ⇒ bbac |
| 17. | bbbaaca ⇒ cac |
| 18. | cacababa ⇒ bbacaaac |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] aa, [2/1] ca, [2/2] ba, [2/3] ac, [2/4] ab, [2/5] bb, [2/6] cb |
|---|---|
| Length 3: | [3/0] aac, [3/1] aba, [3/2] aca, [3/3] aab, [3/4] baa, [3/5] aaa, [3/6] caa |
| Length 4: | [4/0] aaca, [4/1] baac, [4/2] caca, [4/3] baba, [4/4] acaa, [4/5] caaa, [4/6] abaa |
| Length 5: | [5/0] baaca, [5/1] acaaa, [5/2] aabaa, [5/3] aacaa, [5/4] caaac, [5/5] cacaa, [5/6] abaac |
Considering [length 5 / frequency 0] baaca=d.
Rewriting system is complete. See ⟨a, b | aabbabaaaab=1⟩.