| Back: | ⟨a, b | aabbaababba=1⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | babbaa ⇒ abbaab |
| 2. | baababba ⇒ abbaaabb |
| 3. | baaabbaab ⇒ abbaaabba |
| 4. | baabbaababb ⇒ abbaabbabba |
| 5. | bbaaabbaa ⇒ aabbaabab |
| 6. | aaabbaababb ⇒ 1 |
| 7. | baabaabbaabb ⇒ abbaaabbbbaa |
| 8. | baabbaabbbabba ⇒ abbaabbbaababb |
| 9. | abbaaabbbbaaabbaa ⇒ baabab |
| 10. | abbaababbbbaaabbaa ⇒ bbaabab |
| 11. | aaabbaababaabbaabab ⇒ baaabbaa |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ba, [2/1] aa, [2/2] ab, [2/3] bb |
|---|---|
| Length 3: | [3/0] baa, [3/1] abb, [3/2] aab, [3/3] bba, [3/4] bab, [3/5] aaa, [3/6] aba |
| Length 4: | [4/0] bbaa, [4/1] baab, [4/2] abba, [4/3] aabb, [4/4] aaab, [4/5] babb, [4/6] aaba |
| Length 5: | [5/0] abbaa, [5/1] aabba, [5/2] baaba, [5/3] aaabb, [5/4] bbaab, [5/5] baabb, [5/6] aabab |
| Length 6: | [6/0] aabbaa, [6/1] abbaab, [6/2] aaabba, [6/3] baabab, [6/4] baabba, [6/5] baaabb, [6/6] aababb |
| Length 7: | [7/0] aaabbaa, [7/1] aabbaab, [7/2] baababb, [7/3] baabbaa, [7/4] abbaaba, [7/5] bbaabab, [7/6] baaabba |
Considering [length 5 / frequency 0] abbaa=c.
Rewriting system is complete. See ⟨a, b | aabbaababba=1⟩.