Morphocompletion for #3105 ⟨a, b | aabbaabaaab=1⟩

Solved by morph:4/0,4/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. abaabb ⇒ bbaaba
2. aaabaab ⇒ baabaaa
3. baabaaab ⇒ aabbaaba
4. baabbaabaaa ⇒ 1
5. baabaaaaaab ⇒ aaaaabbaaba
6. baabaaaaabb ⇒ aaababbaaba
7. baabaaaaaaaaab ⇒ aaaaaaaabbaaba
8. baabaaaaabaaab ⇒ aaabaaaabbaaba
9. baabaaaaaaaabb ⇒ aaaaaababbaaba
10. baabbaababaabaaa ⇒ abaab
11. baabbaabaabaabaaa ⇒ aabaab
12. baabaaaaaaaaaaaab ⇒ aaaaaaaaaaabbaaba
13. baabbaababaababaabaaa ⇒ abaababaab
14. baabbaababaabaabaabaaa ⇒ abaabaabaab
15. baabbaabaabaababaabaaa ⇒ aabaababaab
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] baa, [3/1] aaa, [3/2] aab, [3/3] aba
Length 4:[4/0] baab, [4/1] abaa, [4/2] aaaa, [4/3] aaba
Length 5:[5/0] baaba, [5/1] aabaa, [5/2] aaaaa, [5/3] abaaa
Length 6:[6/0] baabaa, [6/1] aabaaa, [6/2] aaaaaa, [6/3] baabba

Considering [length 4 / frequency 0] baab=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. acc ⇒ cca
2. acb ⇒ bca
3. ccaaa ⇒ 1
4. aaac ⇒ caaa
5. caaac ⇒ 1
6. caab ⇒ baac
7. ccacaaa ⇒ ac
8. bcaaac ⇒ b
9. acbccaa ⇒ bc
10. acbaac ⇒ b
11. caaab ⇒ aabca
12. baab ⇒ c
13. ccaacaaa ⇒ aac
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ac, [2/2] ca, [2/3] cc, [2/4] ab, [2/5] cb, [2/6] ba
Length 3:[3/0] caa, [3/1] aaa, [3/2] aac, [3/3] cca, [3/4] aab, [3/5] acb, [3/6] baa
Length 4:[4/0] caaa, [4/1] ccaa, [4/2] aaac, [4/3] aaab, [4/4] acba, [4/5] baac, [4/6] bcaa
Length 5:[5/0] acaaa, [5/1] acbaa, [5/2] bcaaa, [5/3] cbaac, [5/4] bccaa, [5/5] caaac, [5/6] acbcc

Considering [length 4 / frequency 0] caaa=d.

Step 3

Rewriting system is complete. See a, b | aabbaabaaab=1⟩.