Morphocompletion for #3079 ⟨a, b | aababbabaab=1⟩

Solved by morph:3/0,3/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. bbaba ⇒ ababb
2. bbbaba ⇒ bababb
3. abbaba ⇒ aababb
4. abbbbaba ⇒ aababbbb
5. abbbbbbaba ⇒ aababbbbbb
6. aababbbbbaba ⇒ aababbbababb
7. aabaababbab ⇒ 1
8. aabaabaababb ⇒ a
9. aabaabaababbbbbb ⇒ abbbb
10. abaabaababbbbab ⇒ bbab
11. abaabaababbbbbbab ⇒ bbbbab
12. aabaababbaababb ⇒ baba
13. aabaabaababababb ⇒ ababa
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa
Length 3:[3/0] aba, [3/1] aab, [3/2] bab, [3/3] bbb
Length 4:[4/0] aaba, [4/1] abaa, [4/2] baba, [4/3] bbbb
Length 5:[5/0] aabaa, [5/1] abaab, [5/2] baaba, [5/3] ababb
Length 6:[6/0] aabaab, [6/1] abaaba, [6/2] aababb, [6/3] baabab

Considering [length 3 / frequency 0] aba=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. cbb ⇒ bbc
2. cccb ⇒ bccc
3. bbccc ⇒ 1
4. bcccb ⇒ 1
5. ccbbc ⇒ cbbcc
6. cbbccc ⇒ c
7. bbcbccc ⇒ cb
8. cbbbccc ⇒ cb
9. bbccbccc ⇒ ccb
10. acbbc ⇒ abbcc
11. abbccc ⇒ a
12. cba ⇒ abc
13. bcca ⇒ accb
14. bccabc ⇒ a
15. bccca ⇒ ccabc
16. aba ⇒ c
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] cc, [2/1] bc, [2/2] cb, [2/3] bb, [2/4] ca, [2/5] ab, [2/6] ba
Length 3:[3/0] ccc, [3/1] bcc, [3/2] bbc, [3/3] ccb, [3/4] cbb, [3/5] cca, [3/6] acb
Length 4:[4/0] bccc, [4/1] bbcc, [4/2] cbbc, [4/3] ccca, [4/4] bcca, [4/5] cabc, [4/6] acbb
Length 5:[5/0] bbccc, [5/1] cbccc, [5/2] bccab, [5/3] ccabc, [5/4] abbcc, [5/5] cbbcc, [5/6] cbbbc

Considering [length 3 / frequency 0] ccc=d.

Step 3

Rewriting system is complete. See a, b | aababbabaab=1⟩.