| Back: | ⟨a, b | aababbaabab=1⟩ |
|---|
Solved by morph:5/0. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: rulesLimit
| # | Rule |
|---|---|
| 1. | baaba ⇒ aabab |
| 2. | babbaab ⇒ ababbba |
| 3. | baaababb ⇒ ababbbaa |
| 4. | abaaababb ⇒ aababbbaa |
| 5. | baaaabab ⇒ aabababa |
| 6. | aaababbbaab ⇒ 1 |
| 7. | ababbbaaaab ⇒ aababababba |
| 8. | baaababbbaa ⇒ 1 |
| 9. | aababababbaab ⇒ ba |
| 10. | aababbababbaab ⇒ bba |
| 11. | aababbbababbaab ⇒ bbba |
| 12. | baaaabaaabab ⇒ aabababaaaba |
| ... |
Collecting factors up to length 8, frequency 7:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb |
|---|---|
| Length 3: | [3/0] aab, [3/1] baa, [3/2] aba, [3/3] bab, [3/4] abb, [3/5] aaa, [3/6] bba |
| Length 4: | [4/0] abab, [4/1] aaba, [4/2] babb, [4/3] baab, [4/4] baaa, [4/5] aaab, [4/6] bbaa |
| Length 5: | [5/0] aabab, [5/1] ababb, [5/2] bbaab, [5/3] aaaba, [5/4] baaab, [5/5] babba, [5/6] baaaa |
| Length 6: | [6/0] aababb, [6/1] aaabab, [6/2] abbaab, [6/3] baaaba, [6/4] baaaab, [6/5] babbaa, [6/6] ababbb |
| Length 7: | [7/0] baaabab, [7/1] aaababb, [7/2] babbaab, [7/3] ababbba, [7/4] baaaaba, [7/5] babbbaa, [7/6] aababbb |
Considering [length 5 / frequency 0] aabab=c.
Rewriting system is complete. See ⟨a, b | aababbaabab=1⟩.