Morphocompletion for #3077 ⟨a, b | aababbaabab=1⟩

Solved by morph:5/0. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baaba ⇒ aabab
2. babbaab ⇒ ababbba
3. baaababb ⇒ ababbbaa
4. abaaababb ⇒ aababbbaa
5. baaaabab ⇒ aabababa
6. aaababbbaab ⇒ 1
7. ababbbaaaab ⇒ aababababba
8. baaababbbaa ⇒ 1
9. aababababbaab ⇒ ba
10. aababbababbaab ⇒ bba
11. aababbbababbaab ⇒ bbba
12. baaaabaaabab ⇒ aabababaaaba
...

Collecting factors up to length 8, frequency 7:

Length 2:[2/0] ab, [2/1] ba, [2/2] aa, [2/3] bb
Length 3:[3/0] aab, [3/1] baa, [3/2] aba, [3/3] bab, [3/4] abb, [3/5] aaa, [3/6] bba
Length 4:[4/0] abab, [4/1] aaba, [4/2] babb, [4/3] baab, [4/4] baaa, [4/5] aaab, [4/6] bbaa
Length 5:[5/0] aabab, [5/1] ababb, [5/2] bbaab, [5/3] aaaba, [5/4] baaab, [5/5] babba, [5/6] baaaa
Length 6:[6/0] aababb, [6/1] aaabab, [6/2] abbaab, [6/3] baaaba, [6/4] baaaab, [6/5] babbaa, [6/6] ababbb
Length 7:[7/0] baaabab, [7/1] aaababb, [7/2] babbaab, [7/3] ababbba, [7/4] baaaaba, [7/5] babbbaa, [7/6] aababbb

Considering [length 5 / frequency 0] aabab=c.

Step 2

Rewriting system is complete. See a, b | aababbaabab=1⟩.