Morphocompletion for #3074 ⟨a, b | aababbaaaab=1⟩

Solved by morph:4/1,2/1. (See Morphocompletion.)

Step 1

Checking up to 20 rules for overlaps.

Rewriting system is not complete: rulesLimit

#Rule
1. baaaabaaba ⇒ aaaabaabab
2. abbaaaaba ⇒ baaaabaab
3. ababbaa ⇒ bbaaaab
4. aababbaa ⇒ abbaaaab
5. aaaabaababb ⇒ 1
6. bbaaaabaab ⇒ aaabaababb
7. babbaaaab ⇒ aabaababb
8. baababba ⇒ abaababb
9. aaaabaababababbaa ⇒ baaaab
10. aaaabaabababaababb ⇒ aababba
11. bbaaaabaaabaababb ⇒ ababba
...

Collecting factors up to length 7, frequency 4:

Length 2:[2/0] aa, [2/1] ba, [2/2] ab, [2/3] bb
Length 3:[3/0] aba, [3/1] baa, [3/2] aab, [3/3] aaa
Length 4:[4/0] aaba, [4/1] babb, [4/2] bbaa, [4/3] abab
Length 5:[5/0] aaaab, [5/1] ababb, [5/2] abbaa, [5/3] baaba
Length 6:[6/0] aaaaba, [6/1] aababb, [6/2] babbaa, [6/3] baabab

Considering [length 4 / frequency 1] babb=c.

Step 2

Checking up to 20 rules for overlaps.

Rewriting system is not complete: roundsLimit

#Rule
1. aaaabaac ⇒ 1
2. baaca ⇒ abaac
3. caaaab ⇒ aabaac
4. bb ⇒ acaaaac
5. bab ⇒ caacaaaa
6. baaaab ⇒ aacaaaaacaa
7. aacaaaaacaaaac ⇒ b
8. babc ⇒ caacaaaac
9. babaac ⇒ acaaaacaaca
10. acaaaacb ⇒ bacaaaac
11. acaaaacab ⇒ bcaacaaaa
12. babacaaaac ⇒ cb
13. babaabaac ⇒ caacaa
14. babaaabaac ⇒ caacaaa
...

Collecting factors up to length 6, frequency 7:

Length 2:[2/0] aa, [2/1] ba, [2/2] ac, [2/3] ab, [2/4] ca, [2/5] cb, [2/6] bc
Length 3:[3/0] aaa, [3/1] aac, [3/2] bab, [3/3] baa, [3/4] aca, [3/5] aba, [3/6] aab
Length 4:[4/0] baac, [4/1] aaaa, [4/2] baba, [4/3] caaa, [4/4] acaa, [4/5] aaac, [4/6] abaa
Length 5:[5/0] abaac, [5/1] caaaa, [5/2] acaaa, [5/3] aaaac, [5/4] babaa, [5/5] aaaab, [5/6] aabaa

Considering [length 2 / frequency 1] ba=d.

Step 3

Rewriting system is complete. See a, b | aababbaaaab=1⟩.