| Back: | ⟨a, b | aabababbaab=1⟩ |
|---|
Solved by morph:2/2,2/1. (See Morphocompletion.)
Checking up to 20 rules for overlaps.
Rewriting system is not complete: arenaTotalLimit
| # | Rule |
|---|---|
| 1. | ababbaab ⇒ aabababb |
| 2. | aabababba ⇒ abbaabaab |
| 3. | aabaabababb ⇒ 1 |
| 4. | abbaabaabab ⇒ 1 |
| 5. | abbaabaaabababb ⇒ baab |
| 6. | aabababbabbaab ⇒ ababbaaabababb |
| 7. | abbaabaabbaabaab ⇒ baaba |
| 8. | aabababbaaabababb ⇒ abbaab |
| 9. | aabababbababbabbaab ⇒ ababbababbaaabababb |
| 10. | aabababbababbababbabbaab ⇒ ababbababbababbaaabababb |
| 11. | aabababbababbababbababbabbaab ⇒ ababbababbababbababbaaabababb |
| 12. | aabababbababbababbababbababbabbaab ⇒ ababbababbababbababbababbaaabababb |
| 13. | aabababbababbababbababbababbababbabbaab ⇒ ababbababbababbababbababbababbaaabababb |
| 14. | aabababbababbababbababbababbababbababbabbaab ⇒ ababbababbababbababbababbababbababbaaabababb |
| 15. | aabababbababbababbababbababbababbababbababbabbaab ⇒ ababbababbababbababbababbababbababbababbaaabababb |
| ... |
Collecting factors up to length 7, frequency 4:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] bb, [2/3] aa |
|---|---|
| Length 3: | [3/0] bab, [3/1] aba, [3/2] abb, [3/3] bba |
| Length 4: | [4/0] abab, [4/1] abba, [4/2] babb, [4/3] baba |
| Length 5: | [5/0] babba, [5/1] ababb, [5/2] babab, [5/3] abbab |
| Length 6: | [6/0] bababb, [6/1] ababba, [6/2] babbab, [6/3] bbabab |
Considering [length 2 / frequency 2] bb=c.
Checking up to 20 rules for overlaps.
Rewriting system is not complete: roundsLimit
| # | Rule |
|---|---|
| 1. | cb ⇒ bc |
| 2. | bb ⇒ c |
| 3. | bacaab ⇒ ababac |
| 4. | abacaab ⇒ aababac |
| 5. | acaabab ⇒ baabaac |
| 6. | acaabaab ⇒ aababaca |
| 7. | baabaab ⇒ acaaba |
| 8. | aababacaac ⇒ b |
| 9. | abababc ⇒ bacaac |
| 10. | aabababc ⇒ abacaac |
| 11. | bababac ⇒ cacaab |
| 12. | aabaababac ⇒ 1 |
| 13. | abaababaca ⇒ 1 |
| 14. | bacaaacaaba ⇒ ab |
| 15. | aababacacaab ⇒ abacaaababac |
| 16. | aababacabacaac ⇒ ababc |
| 17. | aababacababc ⇒ abacabacaac |
| 18. | aababacaaababac ⇒ acaab |
| 19. | aababacabacabacaac ⇒ abacababc |
| ... |
Collecting factors up to length 6, frequency 7:
| Length 2: | [2/0] ab, [2/1] ba, [2/2] aa, [2/3] ac, [2/4] ca, [2/5] bc |
|---|---|
| Length 3: | [3/0] aba, [3/1] aab, [3/2] bac, [3/3] aca, [3/4] bab, [3/5] caa, [3/6] aac |
| Length 4: | [4/0] aaba, [4/1] abab, [4/2] abac, [4/3] baca, [4/4] baba, [4/5] acaa, [4/6] caab |
| Length 5: | [5/0] aabab, [5/1] babac, [5/2] ababa, [5/3] abaca, [5/4] acaab, [5/5] bacaa, [5/6] abaab |
Considering [length 2 / frequency 1] ba=d.
Rewriting system is complete. See ⟨a, b | aabababbaab=1⟩.